The answer is
<span>a) 1000=-16t^2+1700, implies t² = -700 /-16, and t= 6.61s
b) </span><span>970= -16t^2+1700, </span><span>implies t² = -730 /-16, and t=6.75s
c)
reasonable domain of h
h is polynomial function, so its domain is R, (all real number)
its range
the inverse of h is h^-1 = sqrt (1700- t / 16), and its domain is </span>
<span><span><span>1700- t / 16>=0, so t <1700,
the range of h is I= ]-infinity, 1700]</span> </span> </span>
Answer:
ICarly ??
Step-by-step explanation:
I love this show lol
Answer:
9
Step-by-step explanation:
→You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:
\begin{gathered}a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2\end{gathered}
a
2
+b
2
=c
2
x
2
+(x−3)
2
=(x+3)
2
x^2+x^2-6x+9=x^2+6x+9x
2
+x
2
−6x+9=x
2
+6x+9
→Subtract x^2-6x+9x
2
−6x+9 from both sides:
x^2 = 12xx
2
=12x
→Subtract 12x from both sides:
x^2 -12x=0x
2
−12x=0
→Factor out x:
x(x-12)=0x(x−12)=0
→Separate, set = to 0, and solve:
\begin{gathered}x = 0\\x -12=0\end{gathered}
x=0
x−12=0
→ Add 12 to both sides: x = 12x=12
→So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.
→All we need to do is take 12, and plug it into the equation for the shortest leg.
\begin{gathered}x - 3=?\\12-3=9\end{gathered}
x−3=?
12−3=9
Try this option:
1. Odd numbers, which are multiple of 15 and less then 100, are: 15, 45 and 75.
2. the sums of digits are: for 15 is 6, for 45 is 9, for 75 is 12.
3. this number is 75.
It should be 90 because in question it says that
