Question

Hi again here's the picture

Answer 1

Answer:

351.88 m

Step-by-step explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

$= 2( \frac{\pi \: d}{2} + l)$

Plug the values

$= 2( \frac{3.14 \times 42}{2} + 110)$

Calculate the product

$= 2( \frac{131.88}{2} + 110)$

Divide

$= 2 (65.94 + 110)$

Calculate the sum

$= 2 \times 175.94$

Calculate

$= 351.88 \: m$

Hope this helps..

Best regards!!

Answer 2

Answer:

351.88 m²

Step-by-step explanation:

diameter of the semicircle=42  the radius=42/2=21

perimeter of circle=2π r=2(3.14(21))= 131.88(since you have two semi-circle,then it is a full circle)

perimeter of the rectangle: 2(110)=220( the width used to measure the perimeter of the circle)

the area of the track=131.88+220=351.88