One-third of the results of three times a number that is increased by 12.

lesya692 [45]

Isn’t that considered cheating since it’s a test??

7 0

3 years ago

Assuming you are a business owner with different shareholders. How may zero growth stock valuation and constant stock valuation

Katarina [22]

The ways that zero growth stock valuation can affect business operations is that:

When zero-growth model states that the dividend is at the same rate, it shows that one has no measure of growth in terms of dividends. This therefore shows that stock price is equal to the annual dividends and divided also by the needed rate of return.

<h3>What ways does constant stock valuation affect business operations?</h3>

The Constant stock valuation is known to be a kind of share evaluation as it states that the dividends paid by a firm will consistently increase at a constant growth rate.

This will help one to know especially investors on how to set or know the fair price that one needs to pay for a stock on daily basis today by due to future dividend payments.

The overall statement is that stock value affect one's business operations as the company's stock price is one that shows an investor perception of their capability to get profit and also if they can grow their profits in terms of future times.

Learn more about stock valuation from

brainly.com/question/8084221

#SPJ1

7 0

1 year ago

A spinner is divided into 8 equal sections, and each section contains a number from 1 to 8. What is the probability of the spinn

Elodia [21]

Answer:

StartFraction 1 over 8 EndFraction

Step-by-step explanation:

It would be 1/8 because there is 8 sections on the spinner and 5 is on 1 section of the spinner so it would 1/8.

8 0

3 years ago

a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter

andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series $\sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n$ where bn = |an|, converges if $0< b_{n+1} \leq b_n$ for all n, and $\lim_{n \to \infty} b_n =$ 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

Part a

An Alternating series is an infinite series given on these three possible general forms given by:

$\sum_{n=0}^{\infty} (-1)^{n} b_n$

$\sum_{n=0}^{\infty} (-1)^{n+1} b_n$

$\sum_{n=0}^{\infty} (-1)^{n-1} b_n$

For all $a_n >0, \forall n$

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

Part b

An alternating series $\sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n$ where bn = |an| converges if $0< b_{n+1} \leq b_n$ for all n and $\lim_{n \to \infty} b_n$ =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

Theorem (Alternating series test)

If a sequence of positive terms {bn} is monotonically decreasing and

$\lim_{n \to \infty} b_n = 0$ , then the alternating series $\sum (-1)^{n-1} b_n$ converges if:

i) $0 \leq b_{n+1} \leq b_n \forall n$

ii) $\lim_{n \to \infty} b_n = 0$

then $\sum_{n=1}^{\infty}(-1)^{n-1} b_n$ converges

Proof

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

$|s_n -s| < \epsilon$ for all n, and that implies that the series converges to a value, s.

And this complete the proof.

Part c

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where $s_n$ represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most $b_{n+1}$ by the following theorem:

Theorem (Alternating series sum estimation)

If $\sum (-1)^{n-1} b_n$ is the sum of an alternating series that satisfies

i) $0 \leq b_{n+1} \leq b_n \forall n$

ii) $\lim_{n \to \infty} b_n = 0$

Then then $\mid s - s_n \mid \leq b_{n+1}$

Proof

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any two consecutive partial sums sn and sn+1.

$\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}$

And this complete the proof.

5 0

3 years ago

A glassware seller bought 1000 glass tumblers. 100 of them were broken and she sold the remaining tumbler at Rs 80 each. If she

Anton [14]

Answer:

$75

My answer might be a bit off since I'm not really sure what you mean by "Rs 80", which I interpreted as $80, but if my interpretation is wrong, you can still use all the same steps and you should get the correct answer

Step-by-step explanation:

So we can represent the price of each tumbler as the variable "P", since it's some unknown value we're solving for. Let's also just say that "T" is the total price that she paid for all of the tumblers.

Using this equation we can derive the following equation.

1000P = T

Since multiplying the price of each glass tumbler times the price of one glass tumbler should equal the entire price.

Now she only sold 900 of them, since 100 were broken, and she sold them each for 80. So knowing this we can find how much she made in total from selling the remaining 900 glass tumblers

900 * 80 = 72,000

Now if she made a loss of 4%, that means the total money she made back, is only 96% the amount of money she paid for the product. The reason for this is (100-4)% represents a 4% loss.

Remember, how T represents the entire price, well we know that 72,000 represents 96% of it's value. To find what x% is of some number, you generally convert the percentage into a decimal by dividing by 100, so to find x% of some variable "a" you generally use the following equation: $a*\frac{x}{100}$ where the value of this expression will be equal to x% of a.

So let's convert 96% to decimal form: $\frac{96}{100} = 0.96$ . Now if we multiply this decimal 0.96 by T, we should get 72,000 since the 72,000 represents 96% of the original value

$0.96T = 72,000$

To find the original value of T, we simply divide both sides by 0.96

$T = 75,000$

So now that we know the original total price, we can use the original equation we derived to solve for P, which represents the price of each individual tumbler.

Original Equation

$1000P = T$

Substitute 75,000 as T

$1000P = 75,000$

Divide both sides by 1,000

$75=P$

This means she sold each for 75

3 0

1 year ago