Answer:
There is no single answer to this question other than The first graph on the left is the answer. But you should read the explanation and memorize it.
Step-by-step explanation:
It's the first graph on the right. The points are always plotted (without exception) as (x value which means go along the x axis horizontally - left or right.), (y value which means to up (for a plus y) or down for a minus y. These facts are just memorized.
Summary
(x,y)
- x goes either left or right.
- x>0 goes right.
- x<0 goes left.
- y goes up or down
- y > 0 goes up
- y < 0 goes down
Locations
First point (Please label this as first point) - 3 (that goes left) 2 that goes up
You should be putting it in the upper left space.
Second Point. (-2,-2) that goes 2 to left and 2 down. You should put that point in the lower left space. There's only 1 point in the lower left space and that is this point.
Third Point (0,1) That's the only point on the y axis. It is above the x axis. It is all by itself on the y axis line. The other two points are done the same way. Please make sure you try them.
Answer:
i think its B
Step-by-step explanation:
im not sure but im pretty sure if its wrong im sorry but im pretty sure its correct
They had the same quotient because both of those equations are equal
<h3>
sin22° = 5/4</h3><h3>
tan22° = 3/√55</h3>
As we know that , sinA = opposite/hypotenuse & tanA = opposite/adjacent
So here we can find sin22° , because they already given the sides opposite & hypotenuse . And we can't find tann22° because they given the value of opposite but not given the value of adjacent side of the angle 22°
Now finding the adjacent side using
Pythagoras theorem :-
• Hypotenuse² = Base² + Height²
=> 40² = Base² + 15²
=> 1600 - 225 = Base²
=> Base² = 1375
=> Base = √1375
=> Base = 5√55
Now ,
- tan22° = Opposite/Adjacent = 15/5√55 = 3/√55
- sin22° = Opposite/hypotenuse = 15/40 = 5/4
Answer:
Belle is my fav.
Step-by-step explanation:
She loves to read books like me and I hate people who always go out there and try to impress me with something.
