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2 years ago

Determine the slope of the line passing through the given points.

Mathematics

1 answer:

Svetlanka [38]2 years ago

6 0

The slope is -3/1 so to find other points, go to (2,-1) and go down 3, over 1.

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David waits by the crosswalk sign on his way to school. The angle outlined on the sign turns through 50 one-degree angles. Find

mamaluj [8]

Answer:

7 $\frac{1}{5}$ th turns

Step-by-step explanation:

An angle that turn through n one-degrees is said to have an angle measure of n degree. An angle that turns through 1/360 of a circle is called a one degree angle, this is used to measure angles

:. measure of the angle turns through 50 one degree angles

= $\frac{360}{50}$ = 7 $\frac{1}{5}$ th turns.

4 0

3 years ago

What would be the third step in simplifying the expression 4 2 ÷ (2 · 9) + 5?

ludmilkaskok [199]

P
E
M
D
A
S

okay since the first step is parenthesis, the next step would be exponents but you have none so you skip to multiplication, then you divide

divide is your answer

8 0

3 years ago

The length of a couch is 200 centimeters. This is 16 centimeters less than 3 times the width of a matching chair. How wide is th

Snowcat [4.5K]

Answer:

i think the answer is 72

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP NOW I ONLY NEED TO KNOW NUMBER 5. 25 POINTS!!!

Anika [276]

If Point C and D are equidistant from point A, it means that AC and AD are of the same length. AC = AD

AC = AD (S) (<span>Points C and D are equidistant from point A)
</span>AE = AE (S) (The two triangle shared the same side)
∠CAE = ∠EAD (A) (This angle is between the two sides that we just proved to be equal)

By SAS,
ΔEAD ≡ ΔEAC

7 0

4 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

2 years ago