<h2>
Answer:</h2>
The total number of handshakes that would happen between the three people are:
3
<h2>
Step-by-step explanation:</h2>
There are three people at a party.
Let they be denoted by A,B and C.
Now, the total number of handshakes that would occur will be denoted by:
AB, AC and BC
where AB denotes that A and B shake hands.
AC denote that A and C shake hands.
and BC denote that B and C shake hands.
Hence, total number of handshakes are:
3
![\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}](https://tex.z-dn.net/?f=%5Cleft%28%20%5Cfrac%7B27x%5E3%7D%7B8y%5E9%7D%5Cright%29%5E%20%5Cfrac%7B5%7D%7B3%7D%20%20%5C%5C%5C%5C%5C%5C%20%3D%5Cleft%28%20%5Cfrac%7B%283x%29%5E3%7D%7B%282y%5E3%29%5E3%7D%5Cright%29%5E%20%5Cfrac%7B5%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%3D%20%20%5Cfrac%7B%283x%29%5E%7B3%20%5Ctimes%20%20%5Cfrac%7B5%7D%7B3%7D%20%7D%7D%7B%282y%5E3%29%5E%7B3%20%5Ctimes%20%20%5Cfrac%7B5%7D%7B3%7D%20%7D%7D%20%5C%5C%5C%5C%5C%5C%20%3D%5Cfrac%7B%283x%29%5E5%7D%7B%282y%5E3%29%5E%7B5%20%7D%7D%20%5C%5C%5C%5C%5C%5C%20%3D%5Cfrac%7B243x%5E5%7D%7B32y%5E%7B15%7D%7D)
Now, If the exponent was negative like you asked....
F x L = 3x10^10
L = 1x10^-11
F= 3x10^10 / 1x10^-11 = 3x10^21 unit
<O = 16 degrees vertical angles are equal
<O + 4x+90 = 180 DC is a straight line
16 +4x +90 = 180
106 +4x = 180
4x =74
x =18.5
16 +90 +2y= 180 DC is a straight line
106+2y=180
2y = 74
y= 37
Answer : y=37
x=18.5