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podryga [215]
3 years ago
8

Which is the equation of the line with slope 5 that contains point (-2, -3)

Mathematics
2 answers:
lidiya [134]3 years ago
8 0
The answer is y = 5x + 7
here's how you get it:

Start with the base   y = mx + b
then imput the points and the slope:
-3 = 5 ( -2 ) + b

Then solve for b
-3 = 5 ( -2 ) + b
-3 = -10 + b
-b = -7
b = 7

so the equation is:

y = 5x + 7

juin [17]3 years ago
5 0

The answer is y = 5x + 7

here's how you get it:

Start with the base   y = mx + b

then imput the points and the slope:

-3 = 5 ( -2 ) + b

Then solve for b

-3 = 5 ( -2 ) + b

-3 = -10 + b

-b = -7

b = 7

so the equation is:

y = 5x + 7

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Answer:

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Step-by-step explanation:

Base= n

exponent=⁶

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In 4 years, sravani will be 3 times as old as Makayla is currently. three years ago, sravani was 4 times as old as Makayla was t
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x+4=3y\\
x-3=4(y-3)\\\\
x=3y-4\\
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x=3y-4\\
x=4y-9\\\\
3y-4=4y-9\\
4y-3y=-4+9\\
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The measure of an angle is 79 what is the measure of its complementary angle
malfutka [58]

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Step-by-step explanation:

3 0
3 years ago
If a toy rocket is launched vertically upward from the ground level with an initial velocity of 128 feet per second, then its he
natta225 [31]

Answer:

The maximum height of the rocket is 256 feet

Step-by-step explanation:

The vertex form of the quadratic function f(x) = ax² + bx + c is

f(x) = a(x - h)² + k, where

  • (h, k) is the vertex point
  • h = \frac{-b}{2a} and k = f(h)
  • (h, k) is a minimum point if a > 0 and a maximum point if a < 0

Let us use these rules to solve the question

∵ h(t) = -16t² + 128t

→ Compare it by the form of the quadratic function above

∴ a = -16 and b = 128

∵ a < 0

∴ The vertex (h, k) is a maximum point

∴ The maximum height of the rocket is the value of k

→ Use the rule of h above to find it

∵ h = \frac{-128}{2(-16)} = \frac{-128}{-32}

∴ h = 4

→ Substitute x in the equation by the value of h to find k

∵ k = h(h)

∴ k = -16(4)² + 128(4)

∴ k = -256 + 512

∴ K = 256

∴ The maximum height of the rocket is 256 feet

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Craig practiced 15 hours


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