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kkurt [141]
3 years ago
13

Find the quotient. 12^9/12^3 A) 1227 B) 1212 C)126 D) 123

Mathematics
1 answer:
salantis [7]3 years ago
4 0

Answer:

A) 1227

Step-by-step explanation:

\frac{12^9}{12^3}=2985984

12^{3}=1728\\and 12^{9}=5159780352

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Answer:

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Step-by-step explanation:

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2 years ago
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Find the area. 13mm 15mm 26mm 32mm ( PLEASE EXPLAIN or I give 2 stars)​
Ber [7]
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HI can you help me with this question
dolphi86 [110]

Answer:

  42 square centimeters

Step-by-step explanation:

The total of sides FA and AB will be half the perimeter of the rectangle, or 14 cm. Since AB is 9 cm, that means FA is 5 cm.

EF is the difference between EF and FA, so is 11 cm -5 cm = 6 cm.

FC is the same 9 cm length as AB, so we have enough information about the trapezoid to use the area formula:

  A = (1/2)(b1 +b2)h

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The area of the trapezium is 42 cm^2.

6 0
3 years ago
G=h(t) + p(c) is an equation that represents the gross pay of a server: Gross pay = hourly wage (time worked) + percent tip (cos
rusak2 [61]

Answer:

$105.5  for 16 hours at $6.59 per hour

Step-by-step explanation:

form the equation given, G=h(t) + p(c)

where G=Gross pay,

            h= hourly wage

            t=time worked

             p=percent tip

             c=cost of customer meals

we determine the gross pay by first determining the independent variables

h=$4.25, t=16 hours,

p=15%of c\\p=\frac{15}{100}*250 \\p=37.5

if we substitute values, we arrive at

G=h(t)+p(c)\\G=4.25(16)+37.5\G=68+37.5\\G=105.5

to determine the per hour gross pay we have

105.5/16

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3 years ago
The radius of a circle is 8 feet. What is the area of sector bounded by a 90° arc?
Lera25 [3.4K]

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The radius is given by, r = 8 ft, therefore, the area of the full circle is,

\begin{gathered} A=\pi\times r^2 \\ A=3.14\times8^2=200.96ft^2 \end{gathered}

Therefore, the area of the sector is,

A^{\prime}=\frac{1}{4}\times200.96ft^2=50.24ft^2\begin{gathered} A^{\prime}=\frac{\theta}{360}\times\pi\times r^2 \\ \text{ =}\frac{\text{90}}{360}\times\pi\times8^2 \\ \text{ =}\frac{1}{4}\pi\times64=16\pi \end{gathered}

4 0
1 year ago
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