Answer:
A
Step-by-step explanation:
● first one:
The diagonals of a rhombus are perpendicular to each others wich means that they form four right angles.
STP is one of them so this statement is true.
● second one:
If ST and PT were equal this would be a square not a rhombus.
● third one:
If SPQ was a right angle, this woukd be a square.
● fourth one:
Again if the diagonals SQ and PR were equal, this would be a square.
Answer:350,000
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• 1 + cot² x = csc²x and csc x = 
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
sin²Θ( 1 + cot²Θ )
= sin²Θ × csc²Θ
= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified
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Consider the left side
cos²Θ - sin²Θ
= cos²Θ - (1 - cos²Θ)
= cos²Θ - 1 + cos²Θ
= 2cos²Θ - 1 = right side ⇒ verified
The degree of the sum and difference of the polynomials are 6 and 7 respectively.
given polynomials are:


the sum of polynomials = 
the difference of polynomials = 
<h3>what is the degree of a polynomial?</h3>
A polynomial's degree is the highest or the greatest power of a variable in a polynomial equation.
degree of sum = monomial with highest power = 5+1=6
degree of difference = monomial with highest power = 3+4 = 7
therefore, the degree of the sum and difference of the polynomials are 6 and 7 respectively.
to get more about polynomials refer to:
brainly.com/question/1600696