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3 years ago

Write cos 53 degrees in terms of sine.

Mathematics

1 answer:

SOVA2 [1]3 years ago

7 0

Cos(x) = sin(90 - x)
cos(53) = sin(90 - 53)
cos(53) = sin(37)

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Find the equation of the line that is perpendicular to y = –2x + 5 and contains the point

ivann1987 [24]

The given equation is: $y+2x=5$

To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.

The equation to a line perpendicular to it is:

$ 2y-x=c$

where, $c$ is some constant we have determine using the condition given.

It passes through $(2,-1)$

Put the point in our equation:

$2(-1)-(2)=c$

$c=-2-2$

$c=-4$

The final equation is:

$\boxed{ 2y-x=-4}$

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3 years ago

Geometry <br> What is the range of possible values for x? The diagram is not to scale.

Rom4ik [11]

Where is the diagram? How do we answer without it?

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3 years ago

5x=2x+24 what the anwser

d1i1m1o1n [39]

5x=2x+24
5x-2x=24
3x=24
x=24/3
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Now you can verify by putting 8 in the x :)

5 0

2 years ago

Read 2 more answers

The length of a rectangle is 16 feet more than three times the width. The perimeter of the rectangle is 248 feet. Find the dimen

sattari [20]

Answer:

L = 97, w = 27

Step-by-step explanation:

The perimeter formula is P = 2L + 2w. We have too many unknowns simply to plug in, so we have to find a way to identify one in terms of the other. The statement is that the length is 16 feet more than 3 times the width, so the length is in terms of the width and can be identified as

L = 3w + 16

and the width, then, is just w. Now we can fill in those 2 values, both in terms of w, and set it to equal the perimeter value we were given of 248:

2(3w + 16) + 2w = 248 and

6w + 32 + 2w = 248 and

8w + 32 = 248 and

8w = 216 so

w = 27

That means that the width is 27. Use that value of w now to find the length where

L = 3w + 16.

L = 3(27) + 16 and

L = 97

6 0

3 years ago

Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of

leonid [27]

Answer:

$\frac{3}{13} + \frac{2i}{13}$

Step-by-step explanation:

The multiplicative inverse of a complex number y is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = $\frac{1}{3-2i}$

We have that

$(3- 2i)\frac{1}{3-2i} = 1$ would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

$\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}$

Thus, the multiplicative inverse would be $\frac{3}{13} + \frac{2i}{13}$

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

$(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13} =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1$

Thus, the number we found is indeed the multiplicative inverse of 3 - 2i

4 0

3 years ago