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Aneli [31]
3 years ago
12

What equation is graphed in this figure?

Mathematics
2 answers:
romanna [79]3 years ago
8 0

To find equation of the line we need to find out the slope and y intercept

Y intercept is the point where the graph crosses y axis.

In the graph , y intercept is (0,1). so we can also say y intercept is 1.

Now we find out the slope

To find slope we need two points

Lets pick two points from the graph

(0,1) and (-2,4)

Slope m = \frac{y_2-y_1}{x_2 - x_1} =\frac{4-1}{-2 - 0}

m = \frac{-3}{2}

Now we find the equation of the line.

We use y= mx + b

Where m is the slope ( we got m = \frac{-3}{2})

and b is the y intercept ( y intercept is 1 we got)

Replace the values in y=mx+b

y = \frac{-3}{2} x + 1

The equation graphed in the figure is y = \frac{-3}{2} x + 1


Semmy [17]3 years ago
5 0

-3/2 that's the answer idk what else to say lol.

                                                                 

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Convert 31 minutes to seconds​
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What is the area of the figure​
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Formula for the area of a triangle:

( Base X Height ) Divided by 2 or (B×H) ÷ 2

Formula for the area of a circle:

PI times the radius squared or PI × r^2

Area of the triangule part of this figure:

Base: 8ft. Height: 6ft

(8ft × 6ft) ÷ 2

48ft^2 ÷ 2

24ft^2

Since the circular part of the figure is a SEMICIRCLE, we are finding the area of a circle with the same radius but dividing it by 2 since thats just a half of a circle

Area of the semicricle:

Diameter: 10ft,

Therefore the radius is 5ft

(PI x 5ft^2) ÷ 2

39.2699081699 ft^2

39.27 ft^2

Now add these two areas together:

24ft^2 + 38.27ft^2 = 62.27ft^2

Hope it helps

6 0
3 years ago
Suppose that a scuba diver is currently 34 feet below sea level. If he descends at a rate of 2 feet per minute, in how many minu
siniylev [52]
-126 = -34 + 2x is the equation you would use. solve for x, which would be -46. it would take 46 minutes for the diver to reach 126 feet below sea level.
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%
victus00 [196]

Let

\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}

The exponent is indeed 2n-1 - not a typo!

Take the antiderivative of f, denoted by F. This recovers a factor of 2n in the denominator, which lets us condense it to a single factorial.

\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}

Recall the series expansion of sine,

\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}

Then with a little algebraic manipulation, we get

\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x

Differentiate to recover f.

f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}

Finally, f(\pi) = \frac1\pi, so our sum is

\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}

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1 year ago
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