Answer:
1. area of new pen = 11
![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
2. i. 5 feet by 2
feet
ii. 2 ½ feet by 4 ½ feet
Step-by-step explanation:
The size of the pen as planned = 5 ft long by 4 ½ ft wide
Area of the pen = length x width
= 5 x 4 ½
= 5 x ![\frac{9}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B2%7D)
Area of the pen = ![\frac{45}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B45%7D%7B2%7D)
= 22 ½ ![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
But, Krista has to make the pen ½ the size of planned. So that;
area of new pen = ½ x 22 ½
= ½ x ![\frac{45}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B45%7D%7B2%7D)
= ![\frac{45}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B45%7D%7B4%7D)
= 11 ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
area of new pen = 11
![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
The area of the new pen would be 11
.
The possible values she could use are:
i. 5 feet by 2
feet
ii. 2 ½ feet by 4 ½ feet
Find the median first.
78, 80, 83, 85, 86, 87, 90. The middle one is 85, so there's the median. Take the upper half of this set, not including the median, 85, and then subtract 86 from 90. This is 4, so this is the interquartile range.
I do not sorry about that
Answer:
7
Step-by-step explanation:
The standard form of a quadratic equation is
y = ax² + bx + c where a ≠ 1
c is the number without a variable