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saul85 [17]
3 years ago
8

Which one should I choose

Mathematics
2 answers:
Nostrana [21]3 years ago
6 0

Answer:

its the last one

Step-by-step explanation:

the sign flips when you divide by a negative

lapo4ka [179]3 years ago
4 0

9514 1404 393

Answer:

  z ≥ 3

Step-by-step explanation:

When you divide by the negative coefficient of z, you reverse the inequality symbol:

  -8z ≤ -24

  z ≥ -24/-8 . . . . divide by -8

  z ≥ 3

This graphs as a solid dot at 3, with the line extending to the right (to greater values).

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Answer:

I did not understand

Step-by-step explanation:

Why is the question like that

5 0
3 years ago
6x-9=6(x+3). One solution, infinitely many solutions, no solution?
Solnce55 [7]
There is no solution because when you distribute the 6 on the right side you get
6x+18
So the equation is
6x-9=6x+18
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3 years ago
Conservationists have despaired over destruction of tropical rain forest by logging, clearing, and burning." These words begin a
IgorLugansk [536]

Answer: -8.16 to 15.84

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval in which we are a percentage sure the true mean is in the interval.

A confidence interval for a difference between two means and since sample 1 and sample 2 are under 30, will be

x_{1}-x_{2} ± t.S_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}} }

where

x₁ and x₂ are sample means

t is t-score

S_{p} is estimate of standard deviation

n₁ and n₂ are the sample numbers

The estimate of standard deviation is calculated as

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} }

where

s₁ and s₂ are sample standard deviation of each sample

Degrees of freedom is:

df=n_{1}+n_{2}-2

df = 12 + 9 - 2

df = 19

Checking t-table, with 90% Confidence Interval and df = 19, t = 1.729.

The mean and standard deviation for 12 unlogged forest plots are 17.5 and 3.53, respectively.

The mean and standard deviation for 9 logged plots are 13.66 and 4.5, respectively.

Calculating estimate of standard deviaton:

S_{p}=\sqrt{\frac{(12-1)(3.53)^{2}+(9-1)(4.5)^{2}}{12+9-2} }

S_{p}=\sqrt{\frac{299.07}{19} }

S_{p}= 15.74

The difference between means is

x_{1}-x_{2} = 17.5 - 13.66 = 3.84

Calculating the interval:

t.S_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}} } = 1.729.15.74.\sqrt{\frac{1}{12} +\frac{1}{9} }

t.S_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}} } = 27.21\sqrt{\frac{21}{108} }

t.S_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}} } = 27.21\sqrt{0.194}

t.S_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}} } = 12

Then, interval for the difference in mean is 3.84 ± 12, which means the interval is between:

lower limit: 3.84 - 12 = -8.16

upper limit: 3.84 + 12 = 15.84

The interval is from -8.16 to 15.84.

5 0
3 years ago
Consider the function f(x)=−34x+2f(x)=−34x+2 . What is f(4)f(4)?
zlopas [31]
The answer would be x=-134
4 0
3 years ago
Read 2 more answers
Is b+b+b x c+c+c equivalent expressions?<br> A. True <br> B. False
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Answer:

flase

Step-by-step explanation:

3 0
3 years ago
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