Answer:
Neither parallel nor perpendicular
Step-by-step explanation:
I'm assuming you meant line k is y = 3x -2. If not, this is wrong.
For this, you need to put both lines in point-slope form, or the form that line k is already in. This means you only need to convert line m.
-2r + 6v = 18
6v = 2r + 18
v = 2/6r + 18/6
v = 1/3r + 3
Now you can answer the question.
To be parallel, lines must have the same slope (but a different y-intercept). 3 and 1/3 are not the same, so the lines are not parallel.
To be perpendicular, one line must have the opposite reciprocal (fraction flipped and + goes to - or - to +) of the other. While 3 is the reciprocal of 1/3, they are both positive, so they are not perpendicular.
To be the same line, the equations must be absolutely identical, which they aren't.
This leaves the last option: neither.
Let me know if you need a more in-depth explanation of anything here! I'm happy to help!
(-2,5)(1,1)
slope = (y2 - y1) / (x2 - x1)
slope = (1-5) / (1 - (-2) = -4/3
y = mx + b
slope (-4/3)
(1,1)..x = 1 and y = 1
now we sub
1 = -4/3(1) + b
1 = -4/3 + b
1 + 4/3 = b
3/3 + 4/3 = b
7/3 = b
y = -4/3x + 7/3.....(0,T)...x = 0
y = -4/3(0) + 7/3
y = 7/3
check...
(1,1)(0,7/3)
slope = (7/3 - 1) / (0 - 1)
slope = (7/3 - 3/3) / -1
slope = (4/3)/-1 = -4/3
if I did this correctly, I am thinking T = 7/3
43 = 4 tens and 3 ones. (:
10 + 10 + 10 + 10 = 40
1 + 1 + 1 = 3
40 + 3 = 43
Answer:
10
Step-by-step explanation:
Since F is the midpoint of EG, EF and FG are equal. We know that FG is 4 units, so EF must be 4 units. We also know that FH and EF make EH, so we substitute the values that we have.
FH + EF = EH
6 + 4 = EH
EH = 10
