
Let's find out the gradient (Slope " m ") of line q ;



Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :


Now, plug in the value of gradient ~

here we can clearly observe that, the Area under the curve can easily be represented as :

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
Answer:

Step-by-step explanation:
The slope-intercept form is given by y=mx+c, where m is the slope and c is the y-intercept.
Slope of given line= 
Parallel lines have the same slope. Thus, the slope of the line would also be
.

The value of c can be found by substituting a pair of coordinates.
When x= 4, y= -1,

-1= -3 +c
<em>Add 3 to both sides:</em>
c= -1 +3
c= 2
Thus, the equation of the line is
.
Additional:
Do check out the following for a similar question on slope-intercept form!
Answer:
x = -1
Step-by-step explanation:
Solve for x:
3 (2 x - 1) = 7 x + 5 x + 3
Grouping like terms, 7 x + 5 x + 3 = (5 x + 7 x) + 3:
3 (2 x - 1) = (5 x + 7 x) + 3
5 x + 7 x = 12 x:
3 (2 x - 1) = 12 x + 3
Expand out terms of the left hand side:
6 x - 3 = 12 x + 3
Subtract 12 x from both sides:
(6 x - 12 x) - 3 = (12 x - 12 x) + 3
6 x - 12 x = -6 x:
-6 x - 3 = (12 x - 12 x) + 3
12 x - 12 x = 0:
-6 x - 3 = 3
Add 3 to both sides:
(3 - 3) - 6 x = 3 + 3
3 - 3 = 0:
-6 x = 3 + 3
3 + 3 = 6:
-6 x = 6
Divide both sides of -6 x = 6 by -6:
(-6 x)/(-6) = 6/(-6)
(-6)/(-6) = 1:
x = 6/(-6)
The gcd of 6 and -6 is 6, so 6/(-6) = (6×1)/(6 (-1)) = 6/6×1/(-1) = 1/(-1):
x = 1/(-1)
1/(-1) = -1:
Answer: x = -1
Answer:
y = 6
y = 0
y = 0
Step-by-step explanation:

When, x = -2

y = 6
When, x = 0

y = 0
When, x = 4

y = 0
Answer:
The answer is 12.5cm
Step-by-step explanation:
cos 52= 7.7/AC
AC= 7.7/ cos 52
AC= 12.5