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Ksivusya [100]
3 years ago
8

A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept? Explain you

r reasoning.
Mathematics
2 answers:
atroni [7]3 years ago
6 0
A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept? Explain your reasoning. 

<span>p - as "x" never changes with the value of "y", so no matter what y is, x is always "p", so when y is 0, x = p </span>

<span>slope of the line </span>
<span>change in y over the change in x </span>
<span>(-a - a) / (p - p) = infinity - or a vertical line </span>
<span>equation of the line </span>
<span>y = p </span>
<span>slope of a line perpendicular to the given line </span>
<span>inverse of the orig slope or (p - p)/(-a - a) = 0</span>
Alexandra [31]3 years ago
5 0

Answer:

p - as "x" never changes with the value of "y", so no matter what y is, x is always "p", so when y is 0, x = p

Step-by-step explanation:

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y=\frac{-1}{6}x-\frac{10}{3}

Step-by-step explanation:

Slope intercept form of the equation of a line is y=mx+b where m denotes the slope of line and b denotes the y-intercept.

Equation of a line u is y=6x+6

Here, slope of line u = m = 6

As the line v is perpendicular to line u, product of slopes of both the lines is equal to -1.

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As point (10,-5) lies on the line v, put (x,y)=(10,-5) in equation y=\frac{-1}{6}x+b

-5=\frac{-1}{6}(10)+b\\-5=\frac{-5}{3}+b\\ -5+\frac{5}{3}=b\\\frac{-15+5}{3}=b\\\\\frac{-10}{3}=b

Equation of line v is y=\frac{-1}{6}x-\frac{10}{3}

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