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3 years ago

If a function is periodic, with period c, then so is its derivative?

1 answer:

4 0

Think, if something waves up and down at a certain rate, then its slope also will be changing with it along this wave at the same rate. If a function is periodic, with period c, then so is its derivative. I hope that this is the answer that you were looking for and it has helped you.

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NEED HELP ASAP, EASY PROBLEM! Number 4 pls

Solnce55 [7]

The Guzman family=45mph
The Hashimoto family=60mph

3 0

3 years ago

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

$\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2$

$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$

4 0

3 years ago

Write an equation of a line containing (2, 1) and (3, 4) in point-slope form.

ivann1987 [24]

Answer:

$y-1=3(x-2)$

$y-4=3(x-3)$

Step-by-step explanation:

The slope formula is given by:

$m=\frac{y_2-y_1}{x_2-x_1}$

The line containing (2, 1) and (3, 4) has slope;

$m=\frac{4-1}{3-2}=3$

The point-slope form is given by:

$y-y_1=m(x-x_1)$

We substitute the point and slope to get:

$y-1=3(x-2)$

$y-4=3(x-3)$

8 0

3 years ago

The product of two decimals less than 1is less than either of the factors

poizon [28]

This is true for any decimals below 1:
If you multiply a number by something greater than 1, it increases
If you multiply a number by 1, it stays the same
If you multiply a number by something less than 1, it decreases

4 0

3 years ago

3. Consider the following box plot.

forsale [732]

Answer:

2.5

Step-by-step explanation:

And Pls dont do that If you dont know dont answer

3 0

3 years ago