Answer:
104degrees
Step-by-step explanation:
From the given diagram, line LJ bisects KN, hence arcKL = arcHJ
Given
arHJ = 4x
arc KJ = x+39
Equating both
4x = x+39
4x - x = 39
3x = 39
x = 39/3
x = 13
Since arcHK = arcHJ + arcKJ
arcHK = x+39+4x
arcHK = 5x+39
arcHK = 5(13) + 39
arcHK = 65+39
arcHK = 104degrees
Hence the measure of arcHK is 104degrees
Answer:
Time it will take to drain the entire tower = 2.8minutes
Step-by-step explanation:
The question is incomplete as the volume of the tower was not indicated.
Let's consider the following question:
If there are 7.48 gallons in a cubic foot, and the volume of the tower is around 36000in cubed. Residents of the apartment building are using the water from the tower at an average rate of 56 gallons per minute, determine how long it will take to drain the entire tower.
Solution:
Volume = 36000in³
Conversion of in³ to ft³
1 inch = 0.0833 feet
12 inch = 1 ft
1 ft³ = 1ft × 1ft × 1ft
= 12 in x 12 in x 12 in = 1728 in³
36000in³ × [(1ft³)/(1728 in³) = (36000/1728)ft³
= 20.833ft³
Volume = 20.833ft³
There are 7.48 gallons in a cubic foot
In 20.833ft³ = 20.833ft³× (7.48 gallons/1ft³)
= 20.833× 7.48gallons
Volume = 155.83 gallons
The rate of usage = 56 gallons per minute
The rate of usage for 155.83 gallons = 155.83 gallons × (1min/56gallons)
= (155.83/56)minute
= 2.8minutes
Time it will take to drain the entire tower = 2.8minutes
20’ / 5’ = 4
4 x 10” = 40”
40’ /5’ = 8
8 x 10” = 80”
Scaled dimension: 40” x 80”
Answer:
12f-5f²+6f+10f²= 10f²-5f²+12f+6f=5f²+18f
200/3.8= 52.6 mph
This would work because average speed is distance divided by time
