Question

Can somebody please help me?

Answer 1

Part A

We know that √x = 3

Squaring both sides

x = 3²

⇒ x = 9

Hence, the value of x or the minimum value of x is 9

Part B

($\frac{6}{2\pi }$*y²) ÷ (0.4*$\frac{y}{x}$) = ($\frac{6}{2\pi }$*y²) * $\frac{x}{0.4y}$

⇒ ($\frac{6}{2\pi }$*y²) ÷ (0.4*$\frac{y}{x}$) = $\frac{7.5}{\pi y}$*yx