What is the area of a trapezoid if the base is 5, 17, 5 and height is 4

Mathematics

2 answers:

Genrish500 [490]3 years ago

8 0

Answer:

44 units squared.

Step-by-step explanation:

The formula for area of a trapezoid is:

$a = \frac{ b^{1} + {b}^{2} }{2} h$

a = missing area

b1 = short base (5)

b2 = long base (17)

h = height (4)

(5 + 17) ÷ 2 = 11

11 × 4 = 44

area = 44

erica [24]3 years ago

7 0

Answer:

5 + 17) ÷ 2 = 11 So you add 5+17 which is 22, you then divide it by 2 which is 11. 11x4= 44 so 44 units squared. Hope this helped!

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A house on the land measures 45 feet by 38 feet,a wooded area covers 118 feet by 60 feet,and the front yard is 78 feet by 40 fee

Mekhanik [1.2K]

The figure is composed of 2 shapes. A rectangle and a right triangle.

Area of the Rectangle = 600 ft * 200 ft = 120,000 ft²
Area of the right triangle = (600 ft * 450 ft)/2 = 270,000 / 2 = 135,000 ft²

Total area = 120,000 ft² + 135,000 ft² = 260,000 ft²

Area of the house = 45 ft * 38 ft = 1,710 ft²
Area of the woods = 118 ft * 60 ft = 7,080 ft²
Area of the front yard = 78 ft * 40 ft = 3,120 ft²

Area of farmed land = 260,000 - 1,710 - 7,080 - 3,120 = 248,090 ft²

248,090 ft² * 1acre/43,560 ft² = 5.695 acres

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sergey [27]

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Step-by-step explanation: