2 years ago

Find two consecutive odd integers whose product is 899

Mathematics

1 answer:

UNO [17]2 years ago

6 0

Answer:

Step-by-step explanation:

Let two consecutive odd numbers

x, x+2

According to condition

X(x+2) = 899

x2 +2x -899=0

X2 +31x -29x -899=0

x(x+31) -29(x+31)=0

(x+31)(x-29)=0

X=-31 or x =29

Now,

X=29

X+2= 29+2 = 31

Two consecutive odd numbers is 29 and 31

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Find a4 for the arithmetic series with S4=-36 and a1=9

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ANSWER

The 4th term is -27

EXPLANATION

The sum of the first n-terms of an arithmetic sequence is

$S_n= \frac{n}{2} (2a_1+d(n-1))$

It was given that,

$S_4 = - 36$

$a_1 = 9$

$- 36= \frac{ 4}{2} (2 \times 9+d(4-1))$

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$a_4=9+ (4-1) \times -12$

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