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kipiarov [429]
3 years ago
6

What is the solution to this system

Mathematics
1 answer:
NISA [10]3 years ago
5 0

Answer:

the solution to the system is (1,3)

Step-by-step explanation:

x = 1 , y = 3

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4. In a cricket match a batsman hits of boundary 6 time out of 30 balls find the probability
antiseptic1488 [7]

Answer:

here

Step-by-step explanation:

We have been given that, in a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays and we have to find the probability of not hitting boundary. So, the probability of hitting boundary⇒Number of boundaries hitTotal number of balls=630=15.

7 0
2 years ago
The number of square units in the base area of a prism is greater than the number of cubic units in the volume of the prism. Is
Triss [41]

Answer:

3

Step-by-step explanation:

1+1+1=3

7 0
3 years ago
Hailey had 1/5 of a chocolate bar. She decided to
pshichka [43]

Answer:

1/15 each

Step-by-step explanation:

1/5 of chocolate is separated into 3

1/5 divided by 3 = 1/5 x 1/3 = 1/15 of the whole bar

8 0
3 years ago
How many complex roots does the equation below have? X^6+x^3+1=0
gladu [14]
If you find the discriminant it will tell you the number and types of roots. The discriminant is the value b^2 -4ac.
a = 1
b = 1
c = 1
1^2 - 4*1*1
1-4 = -3
Since this is a negative number there will be 2 complex roots.
7 0
3 years ago
Read 2 more answers
Would each of them be able to be the side lengths of a triangle?
ratelena [41]
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

13³=144 + 25


Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
8 0
3 years ago
Read 2 more answers
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