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cestrela7 [59]
2 years ago
13

Solve the equation below for x. log2x + log(2x - 1) = log3x

Mathematics
1 answer:
frosja888 [35]2 years ago
6 0

Answer:

x = 5/4

Step-by-step explanation:

1. cancel x for log 3x and 2x

2. multiply log 2x-1 by log 2

3.simplify to log 4x-2 = log3

4.logs will cancel out and leave you with 4x-2 = 3

5. solve and get 5/4

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Valentin [98]

Answer:

34

Step-by-step explanation:

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3 years ago
Drag each tile to the correct box.
Gwar [14]

Step-by-step explanation:

6x - 15 = 75, 6x = 90, x = 15.

2(2x - 1) = 46, 2x - 1 = 23, x = 12.

x + (x - 10) = 26, 2x = 36, x = 18.

5x - 3x = 10, 2x = 10, x = 5.

Hence the equations

in increasing order of x-values are:

5x - 3x = 10,

2(2x - 1) = 46,

6x - 15 = 75, and

x + (x - 10) = 26.

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3 years ago
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Step-by-step explanation:

4 0
3 years ago
If the outliners are not included in the data set below, what is the mean of the data set?
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7 0
3 years ago
A normally distributed data set has a mean of 0 and a standard deviation of 2. Which of the following is closest to the percent
frutty [35]

A normally distributed data set has a mean of 0 and a standard deviation of 2. The closest to the percent of values between -4.0 and 2.0 would be 84%.

<h3>What is the empirical rule?</h3>

According to the empirical rule, also known as the 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95%, and 99.7% of the values lies within one, two, or three standard deviations of the mean of the distribution.

P(\mu - \sigma < X < \mu + \sigma)  \approx 68\%\\P(\mu - 2\sigma < X < \mu + 2\sigma)  \approx 95\%\\P(\mu - 3\sigma < X < \mu + 3\sigma)  \approx 99.7\%

A normally distributed data set has a mean of 0 and a standard deviation of 2.

Z=(x-\mu)/\sigma

P(x=-0.4)\\\\z=(-0.4-0)/2\\\\= -0.2\\\\P(x=2)\\z=(2-0)/2\\\\=1

P(-0.4 < x < 2)=p(-0.2 < z < 1)=p(-0.2 < z < 0)+p(0 < z < 1)……….(by symmetry)

=.49865+.3413

.83995…….(by (http://83995…….by) table value)

=.8400 × 100

=84%

Learn more about the empirical rule here:

brainly.com/question/13676793

#SPJ2

4 0
1 year ago
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