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exis [7]
3 years ago
5

I hope you can see it please help asap

Mathematics
1 answer:
tiny-mole [99]3 years ago
4 0
After solving, I found the answer to be x=12.
;)
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PLEASE HELP ASAP QUESTIONS ARE IN PICTURE
ArbitrLikvidat [17]

Answer:

1. Last option

2.  third option

Step-by-step explanation:

1.  Each term is formed by multiplying the previous one by 3

so its  729, 2187

2.  Working from right to left we multiply by 5  so its 500.

5 0
3 years ago
Determine whether the relation is a function. {(−3,−6),(−2,−4),(−1,−2),(0,0),(1,2),(2,4),(3,6)}
Gennadij [26K]

Answer:

The relation is a function.

Step-by-step explanation:

In order for the relation to be a function, every input must only have one output. Basically, you can't have 2 outputs for 1 input but you can have 2 inputs for 1 output. Looking at all of the points in the relation, we see that no input has multiple outputs, so the answer is yes, the relation is a function.

7 0
3 years ago
As a salesperson, you are paid $50 per week plus $2 per sale. This week you want your pay to be at least $100. What is the minim
DENIUS [597]
Let s represent the number of sales, and t the total pay
the equation to represent this situation is t = 2s + 50
so set t to 100, and solve for s

100 = 2s + 50
50 = 2s
25 = s

you need to make at least 25 sales
5 0
4 years ago
Solve the following system of equations by substitution. 3x + 2y = -12 x = 2 A. (2, -9) B. (-2, -3) C. (3, 2) D. (2, 3)
Brilliant_brown [7]
Plugging it in, we get (3)(2)+2y=-12 and 6+2y=-12. Subtracting 6 from both sides, we get -18=2y and dividing by 2 we get y=-9  to get (2, -9) since x is first in the pair
4 0
3 years ago
What is the equation of the line perpendicular to y=2x+3.14 going through the points (2,4)?
inessss [21]

Answer:

x+2y-10=0

Step-by-step explanation:

Consider an equation: y=mx+c

Here, m is the slope of the line and c is the y-intercept.

Given equation is y=2x+3.14

Here, slope is m=2

As product of slopes of two perpendicular lines is equal to -1, slope of the required line is m_1=\frac{-1}{m}=\frac{-1}{2}.

Let (x_1,y_1)=(2,4)

Equation of the required line is y-y_1=m_1(x-x_1)

y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0

8 0
3 years ago
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