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GalinKa [24]
3 years ago
7

Usevthe distribute property to express24(3f+6q).​

Mathematics
1 answer:
Reika [66]3 years ago
4 0

Answer:

FACTOR: 8f 3  (3f  6  −2f  4 −4f 3 −4)

Step-by-step explanation:

EVALUATE: 24f 9 −16f  7 −32f  6−32f  3

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A ?<br> B?<br> C ?<br> D? <br> PLEASE
mario62 [17]
C that is the right answer
6 0
2 years ago
Get brainlist!!!!
bonufazy [111]
The answer are
1) gain
Because they asked the price of detergent per load
2) 0.38 per dollar
In this we have to divide 9.25/25
8 0
3 years ago
A school system is reducing the amount of dumpster loads of trash removed each week. In week 5, there were 60 dumpster loads of
Lana71 [14]

Answer:

f(x) = -4x + 80

Step-by-step explanation:

You are given two points,

(5, 60) and (10, 40)

in order to get the equation, let's use the form slope-intercept form

m = (y1 - y2) / (x1 - x2)

m = (60 - 40) / (5 - 10)

m = 20/-5

m = -4

Get the x intercept

y = mx + b

60 = (-4)(5) + b

b = 60+20

b = 80

so the equation is

y = -4x + 80

f(x) = -4x + 80

5 0
2 years ago
Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

8 0
2 years ago
Read 2 more answers
-2.105 as a fraction?
Bezzdna [24]
The easiest way is if it doesn't need to be simplified. Multiply -2.105 by \frac{1000}{1000}. You get the fraction -\frac{2105}{1000}. While this is technically the answer, you can simplify this down to \frac{421}{200}. Because 421 is a prime number, this can not be simplified any further. Therefore, the solution is \frac{421}{200}.

\frac{421}{200}.
6 0
2 years ago
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