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vagabundo [1.1K]
3 years ago
7

HELP!

Mathematics
2 answers:
pashok25 [27]3 years ago
7 0
Multiplying both sides of    <span>−1/3x≤−6    by -3 results in "x is equal to or greater than 18."
 
Note that multiplying such an inequality requires reversing the direction of the inequality symbol.

I subst. 18 for x in   </span><span>−1/3x≤−6    as a check, and found that  the resulting inequality is true.</span>
____ [38]3 years ago
4 0

Answer:

x \geq 18

Step-by-step explanation:


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What is the equation of the line which has a gradient of 2 and passes through the point (1,4)
timofeeve [1]

Answer:

Y= 2x+2

Step-by-step explanation:

line equation is y=mx +c


m is the gradient = 2

We are given an x and y value

X= 1
y= 4


substitute that into the equation:

4= 2(1) +c

2=c


Put all the equation together:

Y= 2x+2

5 0
2 years ago
Given that 5 x − 3 y = 32 Find y when x = 4
ollegr [7]

Answer:

<h2><em>y</em><em>=</em><em>-</em><em>4</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>X=</em><em>4</em>

<em>Now</em><em>,</em>

<em>5x - 3y = 32 \\ or \: 5 \times x - 3y = 32 \\ or \: 5 \times 4 - 3y = 32 \\ or \: 20 - 3y = 32 \\ or \:  - 3y = 32 - 20 \\ or \:  - 3y = 12 \\ or \: y = -   \frac{12}{ 3}  \\ y =  - 4</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

4 0
3 years ago
Read 2 more answers
Find the opposite of -3
WITCHER [35]
The opposite would be 3

__

4
Just switch out the negatives for positives
8 0
3 years ago
Read 2 more answers
Marking brainliest <br><br> Please help
Ugo [173]
I think the answer is plus bc you need to add
5 0
3 years ago
Read 2 more answers
Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
DedPeter [7]
Using polynomial long division, we get
         
         3x^3+6x^2+11x
         _____________
(x+2) | 3x^4-x^2+cx-2
          -(3x^4+6x^3)
          ____________
             6x^3-x^2+cx-2
          - (6x^3+12x^2)
         _____________
        11x^2+cx-2
      -(11x^2+22x) 
       __________
        (22+c)x-2. 

If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
4 0
3 years ago
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