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eimsori [14]
3 years ago
11

WORTH 90 POINTS!

Mathematics
2 answers:
nadya68 [22]3 years ago
6 0

A. Just add the given sides.

8y^2+8y-10 is the answer.

B. The perimeter of any shape is all the sides added together. The perimeter given is the perimeter of the quadrilateral, and we are to find the other side. We are given values of three sides. We can find the value of the other side by subtracting the sum of those three sides from the total perimeter:


(22y^3+10y^2+10y-17)-[(4y+2y^2-3)+(-4+2y^2+2y)+(4y^2−3+2y)]

When simplified, you get 22y^3+2y^2+2y-7.

C. The polynomials are closed under addition and subtraction as the result is another polynomial. It can be justified by parts A and B.



Hope this helps.


scoray [572]3 years ago
6 0

A. total length of side 1-3 = side 1 + side 2 + side 3

Side 1: 4y + 2y2 − 3

Side 2: −4 + 2y2 + 2y  

Side 3: 4y2 − 3 + 2y

so total = 8y^2 + 8y - 10


B. perimeter = sum of side 1-4

so length of side 4 = perimeter - total of side 1-3

= 22y3 + 10y2 + 10y − 17 - (8y^2 + 8y - 10)

= 22y^3 + 2y^2 + 2y - 7


C. they are close for addition and subtraction. Part A and B show that.


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If anyone could solve this question for me while showing the steps. It would be GREATLY appreciated
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this is a very annoying problem, with lots of steps. it is on a next level of dragging on and on

Step-by-step explanation:

You can split this into different shapes. A triangle, a rectangle, and a void of a quarter circle. The total area is rectangle+triangle-quarter circle.

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Fencing first:

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if you find anything wrong message me, I may have made errors because its 10pm and i need sleep. I recommend you work through my steps on your own as well. There might be complications with rounding as well, so yea. Hope this helps!

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