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harkovskaia [24]
3 years ago
11

How do you know when energy is moving in a lightbulb circuit?

Computers and Technology
1 answer:
vagabundo [1.1K]3 years ago
4 0
When energy flows in the Electric Circuit then Light bulb blows and emits light energy and thermal energy. By that sign, we can get an idea that energy is flowing.

Hope this helps!
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The ____ layer of the osi model performs a series of miscellaneous functions necessary for presenting the data package properly
Darya [45]
The "transport" layer of the OSI model performs a series of miscellaneous functions
Machine function also called miscellaneous functions—influence. positive functions on the machine, such as diverting the spindle rotation and coolant on and off, the path action of the tool, and the program beheading.
7 0
3 years ago
Su now wants to highlight several inventors in her presentation, so she decides to use the underline color option.
Mars2501 [29]

Answer:

1. The home tab

2. Font group

3. The small arrow at the bottom right of the font command group.

4. On "Font" heading (then "All text" subheading)

Explanation:

The following explanation will help Su in accomplishing her task.

1. Go to the home tab;

2. From the home tab, Su will have access to various command groups but in her case, she needs the Font command group.

3. There's a small arrow located at the bottom left of the font command group section; clicking on this arrow will open the font dialogue.

4. On the font dialogue, there are two headings. The "font" heading and the "character spacing" heading.

In her case, she needs the "Font" heading. The font heading also has various subheadings. To access the underline colour option, she needs the "All text" subheading.

See attachment for picture guide.

7 0
3 years ago
Which of the following tasks are suitable for creating an algorithm? Choose all that apply.
Nookie1986 [14]

Answer:

All except saving time writing a computer program.

3 0
3 years ago
Who watched Unus Annus??? (If you did what was your favorite part?​
quester [9]

This video was completeley unedited was a banger, and so was the vid where they made robot amy. that was hilarious.

But since it is now Post Mortem all say here is...

Unas Annus. Memento Mori.

It sure was fun.

3 0
2 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
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