Answer:
Common Internet File System
Explanation:
Given that the Server Message Block (SMB) has various types or variations. The most common variation of this Server Message Block sharing protocol that is considered to be a dialect of SMB is known as "Common Internet File System." This is known to serve as a form of a communication protocol for giving shared access to different outlets between nodes on a network.
Hence, in this case, the correct answer is "Common Internet File System"
Answer:
The time elapsed is 0.017224 s
Solution:
As per the question:
Analog signal to digital bit stream conversion by Host A =64 kbps
Byte packets obtained by Host A = 56 bytes
Rate of transmission = 2 Mbps
Propagation delay = 10 ms = 0.01 s
Now,
Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.
Time taken to generate and convert all the bits into digital signal is given by;
t = 
t = 
(Since, 1 byte = 8 bits)
t = 7 ms = 0.007 s
Time Required for transmission of the packet, t':
Now, the time elapse between the bit creation and its decoding is given by:
t + t' + propagation delay= 0.007 + 
+ 0.01= 0.017224 s
Answer:
Explanation:
Exercise A:
1. A table.
2. Categorical.
3. Access.
4.Queries.
5.ACCDB extension.
Exercise B:
1. Insert Tab.
2. DoCmd.Quit method.
3.Navigation Pane.
4. Modify table data.
5.The top pane and the bottom pane.
Hope this helped you!
Answer:
(a) What is the best case time complexity of the algorithm (assuming n > 1)?
Answer: O(1)
(b) What is the worst case time complexity of the algorithm?
Answer: O(n^4)
Explanation:
(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1)
.
(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).
