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3 years ago

You need a quart of water but you only have a measuring cup. How many times do you need to fill the cup in order to get a quart?

Mathematics

1 answer:

larisa86 [58]3 years ago

6 0

You need to fill the cup up 4 times since there are 4 cups in a quart.

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A gym employee is paid monthly.after working for 3 months he had earned $4,500. To determine how much money he will make over a

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He would make $9,000 in 6 months

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3 years ago

Find the number the comes next 1.2.6,21.88,?

Nataly_w [17]

Answer

455

Step-by-step explanation:

(1×1) + 1 = 2

(2×2) + 2 = 6

(6×3) + 3 = 21

(21×4)+4 = 88

(88×5)+5 = 445

5 0

2 years ago

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Suppose E is an event whose probability of occurring is

bixtya [17]

Answer:

D. 1/3

Step-by-step explanation:

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2 years ago

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A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

6 0

3 years ago

When A is divided by the sum of a certain number and 10, the result is the same as dividing 3 by the sum of that number and 4 .

tensa zangetsu [6.8K]

When A is divided: A /

By the sum of a certain number and 10: (n + 10)

When A is divided by the sum of a certain number and 10: A / (n + 10)

The result is the same as: =

Dividing 3: 3 /

By the sum of that number and 4: (n + 4)

The result is the same as dividing 3 by the sum of that number and 4: 3 / (n + 4).

Final Equation: A / (n + 10) = 3 / (n + 4)

To solve, we'll need to cross-multiply. Without knowing the value of A, however, the answer will not be a numerical value.

3(n + 10) = A(n + 4)

3n + 30 = An + 4A

30 - 4A = An - 3n

30 - 4A = n(A - 3)

n = (30 - 4A) / (A - 3)

If you know the value of A, then please plug it in to the value for n given above.

Hope this helps!

5 0

1 year ago

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