We have been given that last month Maria purchased a new cell phone for $500. The store manager told her that her cell phone would depreciate by 70% every 6 months.
We know that an exponential function is in form
, where,
y = Final value,
a = Initial value,
r = Decay rate in decimal form,
x = Time in years.
Let us convert
into decimal form.
![70\%=\frac{70}{100}=0.70](https://tex.z-dn.net/?f=70%5C%25%3D%5Cfrac%7B70%7D%7B100%7D%3D0.70)
Initial value of car is 500, so
.
Since value of phone depreciates every months, so value of phone will depreciate twice in a year.
Upon substituting our given values in exponential decay function, we will get:
![V=500(1-0.70)^{2x}](https://tex.z-dn.net/?f=V%3D500%281-0.70%29%5E%7B2x%7D)
To find the value of phone after 2 years, we will substitute
in our equation.
![V=500(1-0.70)^{2(\cdot 2)}](https://tex.z-dn.net/?f=V%3D500%281-0.70%29%5E%7B2%28%5Ccdot%202%29%7D)
![V=500(1-0.70)^{4}](https://tex.z-dn.net/?f=V%3D500%281-0.70%29%5E%7B4%7D)
Therefore, option D is the correct choice.
Let us simplify our equation.
![V=500(0.30)^{4}](https://tex.z-dn.net/?f=V%3D500%280.30%29%5E%7B4%7D)
Therefore, option B is correct as well.