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4 years ago

PLEASE HELP ME!!!! ill mark 1st persons answer as brainliest

Mathematics

1 answer:

kari74 [83]4 years ago

7 0

$(x+2y)( x-5y) = \\ \\ x^2-5xy+2yx-10y^2= \boxed{x^2-3xy-10y^2} \to Step \ 4$

I wish you much success in your studies!!!!

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A mixed economy is dependent only on the choices of individuals and businesses a combination of individual choice and government

bekas [8.4K]

Answer:

In general, a mixed economy is "a combination of individual choice and government protection," although the balance tends to lean more towards individual choice.

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2 years ago

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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3 years ago

Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is 13.4 years with a s

Aliun [14]

Answer : 0.0129

Step-by-step explanation:

Given : Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is $\mu=13.4$ years and standard deviation is $\sigma=1.7$ years.

Sample size : $n=40$

Let X be the random variable that represents the age of fleets.

We assume that the ages of the fleets of the 10 largest U.S. commercial passenger carriers are normally distributed.

For z-score,

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For x=14

$z=\dfrac{14-13.4}{\dfrac{1.7}{\sqrt{40}}}\approx2.23$

By using the standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be :-

$P(x\geq 14)=P(z\geq2.23)\\\\=1-P(z$

Hence, the required probability = 0.0129

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3 years ago

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Greeley [361]

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3 years ago

What will make 3/10 n= 4/5?

Paladinen [302]

Answer:

put 8/3

Step-by-step explanation:

Given

$\frac{3}{10} n \: = \frac{4}{5} \\ inserting \: n \: = \frac{8}{3} \: we \: get \: \\ \frac{3}{10} \times \frac{8}{3} = \frac{4}{5} \\ cancel \: 3 \: an d \: divide \: 8 \: and \: 10 \: by \: 2 \\ we \: get \\ \frac{4}{5} = \frac{4}{5}$

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3 years ago