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Scorpion4ik [409]
3 years ago
6

LOOK AT THE PICTURE TO ANSWER

Mathematics
2 answers:
lesantik [10]3 years ago
7 0
I think it’s 15 I’m not sure tho
Wittaler [7]3 years ago
3 0
D) -65
Hope this helps
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Solve the differential equation dy dx equals the quotient of x squared and y squared for y = f(x) with the initial condition y(0
Gnoma [55]
\displaystyle\frac{dy}{dx} = \frac{x^2}{y^2}\ \Rightarrow\ y^2 dy = x^2 dx\ \Rightarrow\ \int y^2 dy = \int x^2 dx\ \Rightarrow\textstyle\ \frac{1}{3}y^3 = \frac{1}{3}x^3 + C. \\ \\
\text{Now } y(0) = 2\ \Rightarrow\ \frac{1}{3}(2)^3 = \frac{1}{3}(0)^3 + C\ \Rightarrow\ \frac{8}{3} = C,\text{ so } \frac{1}{3}y^3 = \frac{1}{3}x^3 + \frac{8}{3}. \\ \\
y^3 = x^3 + 8\ \Rightarrow\ y = \sqrt[3]{x^3 + 8}
7 0
3 years ago
Noah has meter of rope . How many pieces of rope of length 1/2 meter can he cut from it ? Draw a diagram to illustrate your solu
muminat
2? if he had only one meter that would be correct
5 0
3 years ago
Read 2 more answers
Which is answer is correct
horsena [70]

Answer:

i think it is b and c im trying

Step-by-step explanation:


6 0
3 years ago
Can u please help me with this 2 problem please
Mice21 [21]
<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
  • map scale = 1.5 in : 5 mi
<h3>Find</h3>
  • actual distance
<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

6 0
3 years ago
Find the location of the center of a circle if the endpoints of the diameter are at (-10,
Artyom0805 [142]

Answer:

(- 1, - \frac{1}{2} )

Step-by-step explanation:

The centre is located at the midpoint of the diameter.

Using the midpoint formula , then

centre = \frac{-10+8}{2}, \frac{-5+4}{2} ) = ( \frac{-2}{2}, \frac{-1}{2} ) = (- 1, - \frac{1}{2} )

7 0
3 years ago
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