We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 
When two lines are parallel, then the slopes of the two lines are equal.
Equation of line with point 
and slope 'm' is given by:
Since, we have to determine the equation of a line with point (2,-5).
So, the equation of the line is : 
Since, the line is parallel to the line 
So, 
So, slope of the line 'm' is 
.
Therefore, the equation of the line is:
Therefore, is the required equation of the line.
Tan 60 in radical for is square root of 3
Answer:
Step-by-step explanation:
Additive inverse of (5a² - 4a + 3) should be added to make them zero
(5a² - 4a + 3) + (-5a² + 4a - 3)= <u>5a² - 5a² </u> <u>- 4a + 4a</u> <u>+ 3 - 3</u>
= 0
he volume of the solid under a surface
z
=
f
(
x
,
y
)
and above a region D is given by the formula
∫
∫
D
f
(
x
,
y
)
d
A
.
Here
f
(
x
,
y
)
=
6
x
y
. The inequalities that define the region D can be found by making a sketch of the triangle that lies in the
x
y
−
plane. The bounding equations of the triangle are found using the point-slope formula as
x
=
1
,
y
=
1
and
y
=
−
x
3
+
7
3
.
Here is a sketch of the triangle:
Intersecting Region
The inequalities that describe D are given by the sketch as:
1
≤
x
≤
4
and
1
≤
y
≤
−
x
3
+
7
3
.
Therefore, volume is
V
=
∫
4
1
∫
−
x
3
+
7
3
1
6
x
y
d
y
d
x
=
∫
4
1
6
x
[
y
2
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
y
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
49
9
−
14
x
9
+
x
2
9
−
1
]
d
x
=
3
∫
4
1
40
x
9
−
14
x
2
9
+
x
3
9
d
x
=
3
[
40
x
2
18
−
14
x
3
27
+
x
4
36
]
4
1
=
3
[
(
640
18
−
896
27
+
256
36
)
−
(
40
18
−
14
27
+
1
36
)
]
=
23.25
.
Volume is
23.25
.
If the area of a parallelogram is given as with a height of , we can refer back to the equation for the area of a parallelogram: \displaystyle A= b \cdot h, where is height and is the length of the base.
