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3 years ago

The mean of 4.8,1.5,6.3,6.7,8.3

Mathematics

1 answer:

Effectus [21]3 years ago

5 0

Answer:

5.52

Step-by-step explanation:

To calculate the mean of a set, all you have to do is divide the sum of all elements in the set by the number of elements in the set. Therefore, the mean for this set would be (4.8 + 1.5 + 6.3 + 6.7 + 8.3) / 5 = 5.52.

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Answer:

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3 years ago

Which represents a total cost of 2 dance tickets at a price of c for each, less a one-time $5 discount?

Eduardwww [97]

The statement is represented as 2(c- 5). Option D

<h3>What are algebraic expressions?</h3>

Algebraic expressions are expressions consisting of variables, terms, factors, and constants.

They are also made up of mathematical operations such as addition, bracket, subtraction, division, multiplication, etc

From the information given, we have;

total cost of 2 dance tickets
price of c for each, less a one-time $5 discount

Expressed as;

2(c- 5)

Thus, the statement is represented as 2(c- 5). Option D

Learn more about algebraic expressions here:

brainly.com/question/4344214

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7 0

1 year ago

Hi, can someone please help me with this question, I'm a bit baffled.

liq [111]

-1(3x-2y=27)
3x-y=24
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y=-3
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3x+3=24
-3. -3
3x=21
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Hope that helps

7 0

3 years ago

Read 2 more answers

Which of the following pairs of numbers contains like fractions? A.3/2 and 2/3 B.5/6 and 10/12 C. 6/7 and 1 5/7 D. 3 1/2 and 4 4

AVprozaik [17]

B would be the correct answer

7 0

4 years ago

Hw 28 shades figure

ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

Part 10) $SF=0.5, x=14\ ft$

Part 11) $SF=0.5, x=3.5\ ft$

Part 12) $SF=3, x=7\ m$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

4 years ago

The mean of 4.8,1.5,6.3,6.7,8.3 ​

The mean of 4.8,1.5,6.3,6.7,8.3