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Talja [164]
3 years ago
7

Corey and Margaret went scuba diving in the ocean together. Corey dove to a depth of -23 feet, while Margaret dove to a depth of

-45 feet. Who dove deeper into the ocean?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
Margaret dove deeper
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The speed of a garden snail is about 8.5×10−6 miles per second. If a garden snail moves at this speed in a straight line for 2×1
BaLLatris [955]

Answer:

17*10^-3 miles

Step-by-step explanation:

Given data

Speed= 8.5×10^−6 miles per second

Time taken=2×10^3 seconds

We know that the expression for the speed is given as

speed= distance/time

distance= speed* time

substitute

distance= 8.5×10^−6* 2×10^3

distance= 8.5*2*(10^-6+3)

distance= 17*10^-3 miles

6 0
3 years ago
Use a 30degrees and -60degrees right triangle to find the exact value of the following trigonometric expression. Cot 30 degrees=
LuckyWell [14K]

The dirty little secret about trig is students mostly just need to understand the 45/45/90 right isosceles triangle and the 30/60/90 triangle, which is half an isosceles triangle.  

I'm sure you have seen it many times already, so I'll remind you in the 30/60/90 right triangle the sides opposite those angles are respectively in the ratio 1: \sqrt{3}:2.  Remember the smallest side is always opposite the smallest angle, etc.   These make a right triangle because

1^2 + \sqrt{3}^2 = 2^2

So in this hypotenuse 2 triangle, the length 1 side is opposite the 30 degree angle and the \sqrt{3} side is adjacent to it.

We could jump right to the answer but let's enumerate all the trig functions.  Really you should memorize the sine and cosine so you can get these quickly.

\cos 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{hypotenuse} } = \dfrac{\sqrt{3}}{2}

\sin 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{hypotenuse} } = \dfrac{1}{2}

\tan 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{adjacent} }= \dfrac{1}{\sqrt{3}} =\dfrac{\sqrt{3}}{3}

\cot 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{opposite}} = \dfrac{\sqrt{3}}{1} =\sqrt{3}

\sec 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{adjacent}}= \dfrac{2}{\sqrt{3}}

\csc 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{opposite}}= \dfrac{2}{1} = 2

We want the cotangent, another way to get it is

\cot 30^\circ = \dfrac{\cos 30^\circ}{\sin 30^\circ} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}

8 0
3 years ago
Read 2 more answers
What is the area of the base?
omeli [17]

Answer:

20

Step-by-step explanation:

The area can be calculated by Length times width. The length is 10 and the width is 2 so 10 x 2 = 20

Cheers

8 0
3 years ago
Read 2 more answers
Ruben bought 6 comic books for $21. Each comic book was the same price. What is the price for 1 comic book?
Mars2501 [29]

Answer:

Each comic booke was $3.50

Step-by-step explanation:

You just have to divide 21 by 6

3 0
3 years ago
Read 2 more answers
Solve for a<br><br> - 8a = 24
Amanda [17]

Answer:

a = -3

Step-by-step explanation:

Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other.

Divide -8 from both sides:

(-8a)/-8 = (24)/-8

a = 24/-8

a = -3

a = -3 is your answer.

6 0
3 years ago
Read 2 more answers
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