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Mamont248 [21]
3 years ago
13

How to determine if vectors are parallel?

Mathematics
1 answer:
sattari [20]3 years ago
3 0
One could use the relation

\mathbf a\cdot\mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta

where \mathbf a,\mathbf b are two vectors, \|\mathbf a\| denotes the norm of that vector, and \theta is the angle between the two vectors.

Then the two vectors will be parallel if \theta=0 or \pi.
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Please help.
Bad White [126]

Answer:

Parallel: a and b, p and q, p and r, q and r

PErpendicular: p&a, p&b, q&a, q&b, r&a, r&b

Step-by-step explanation:

Parallel lines have the same slope so both of the lines would be going in the same direction and will never cross each other.

Perpendicular lines cross at a 90 degree angle.

Technically you do not know if q&a and q&b are perpendicular because you do not know if there is a 90 degree angle

7 0
3 years ago
Read 2 more answers
An artist is using right triangles in her design. If all the
katovenus [111]
I think it’s C because a triangle is 180 degrees and it’s a right triangle which means there is a 90 degrees angle + 30 degrees.
90+30=120. 180-120=60
Which means the third angle is 60 degrees
3 0
3 years ago
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Calculate the median of the following data set: {2, 22, 8, 6, 19, 15, 5, 12} 6 19 10 2​
VMariaS [17]

Answer:

10

Step-by-step explanation:

median is the middle number

these numbers in order are 2, 5, 6, 8, 12, 15, 19, 22 and the middle numbers are 8 and 12

to ind the middle number of those two numbers, you find the mean (averge) of those numbers

mean: 8+12=20/2=10

lmk if its right!

3 0
3 years ago
What is the simple ratio of 1 ½km to 900m​
LekaFEV [45]
I think it would be 1:600
7 0
3 years ago
The diagonals of a convex quadrilateral are mutually perpendicular. The sum of the lengths of the diagonals is 12. We want to fi
KIM [24]

Answer:

33

Step-by-step explanation:

Step 1: The Diagonals of the Convex Quadilateral are Mutually Perpendicular this makes the shape a Rhombus Shape

Step 2: The formula for a area of a rhombus is the multiply the two lengths and divide by two.

In this Question we have x×y÷2 or xy/2

Step 3: The sum of the lengths of the diagonals is 12

x+y=12

y=12-x

Therefore, the area, as a function of x alone = x(12-x)/2

Step 4: To find the maximum area, let's find the derivative of the area function in respect to x and then equate to 0.

d/dx(x(12-x)/2)=0

d/dx(12x - x^2) = 0

12-2x=0

12-0=2x

12=2x, divide both sides by 2

x= 6

Step 5: Calculate the Maximum Area

The maximum area will then be 6(12 - 6)/2

= (72-6)/2 = 66/2= 33

So, the maximum area is 33.

3 0
3 years ago
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