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9966 [12]
4 years ago
13

Suppose an investment of $10,000 doubles in value every 13 years. How much is the investment worth after 52 years? After 65 year

s?
A: $80,000; $100,000

B: $160,000; $320,000

C: $520,000; $650,000
Mathematics
2 answers:
KengaRu [80]4 years ago
7 0
The answers A: $80,000; $100,000
Alborosie4 years ago
7 0

Answer:


Step-by-step explanation:

The answer is actually B. $160,000; $320,000

The reason for this is because -

$10,000 is the constant, so let a= 10,000.

The investment doubles every 13 years, so let b=2.

Let x= the number of 13-year periods.


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Pls answer! I don’t know math @ all
Lana71 [14]

The probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

Solution:

Total number of outcomes N(S) = 36

Let A be the sum that is a multiple of 6 and

B be the sum that is a multiple of 4.

Sum that is a multiple of 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (6, 6)

N(A) = 6

Sum that is a multiple of 4 = (1, 3), (2, 2), (2, 6), (3, 1), (3, 5),

                                              (4, 4), (5, 3), (6, 2), (6, 6)

N(B) = 9

$P(A)=\frac{N(A)}{N(S)}

$P(A)=\frac{6}{36}=\frac{1}{6}

$P(B)=\frac{N(B)}{N(S)}

$P(B)=\frac{9}{36}=\frac{1}{4}

Probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4:

P(A \cup B)=P(A)+P(B)

$P(A \cup B)=\frac{1}{6} +\frac{1}{4}

               $=\frac{2+3}{12} (Make the denominator same)

               $=\frac{5}{12}

Hence the probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

8 0
3 years ago
Can someone help me please an thank you
Gala2k [10]
A.c because it’s right
6 0
3 years ago
If y=x^2+2x find the value of y when x =3
Brilliant_brown [7]
X=3 so

3^2= 9

2*3= 6

y= 9 + 6

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3 years ago
Debbie has at most $60 to spend on the clothes. She wants to buy a pair of jeans for $22 and spend the rest on t-shirts. Each t-
kvasek [131]
The answer is D! Hope this helps <3
3 0
3 years ago
If mc022-1.j pg and mc022-2.j pg, what is the value of (f – g)(144)? –84 –60 0 48
Mashutka [201]

Answer:

0

Step-by-step explanation:

f(x) = √(x) + 12

g(x) = 2√(x)

(f-g)(x) = √(x) + 12 - 2√(x)

(f-g)(x) = 12 - √(x)

if x = 144

(f-g)(144) = 12 - √(144) = 12 - 12 = 0

5 0
4 years ago
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