Question

If mc022-1.j pg and mc022-2.j pg, what is the value of (f – g)(144)? –84 –60 0 48

Answer 1

Answer:

(f-g) (144) = 0.

Step-by-step explanation:

Given : f(x) = $\sqrt{x}+12$ and g(x) =  $2\sqrt{x}$ .

To find : what is the value of (f – g)(144).

Solution : We have given

By the formula :  (f – g)(x) = f(x) - g(x)

(f – g)(144) = f(144) - g(144).

f(x) - g(x) = $\sqrt{x} +12 -2\sqrt{x}$.

(f-g) (x) = 12 - $\sqrt{x}$.

(f-g) (144) = 12 - $\sqrt{144}$.

(f-g) (144) = 12 -12

(f-g) (144) = 0.

Therefore, (f-g) (144) = 0.

Answer 2

Answer:

0

Step-by-step explanation:

f(x) = √(x) + 12

g(x) = 2√(x)

(f-g)(x) = √(x) + 12 - 2√(x)

(f-g)(x) = 12 - √(x)

if x = 144

(f-g)(144) = 12 - √(144) = 12 - 12 = 0