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user100 [1]
3 years ago
6

I will give BRAINLIEST to whoever is correct.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0
The answer would be ab+ac
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A) 20 milligrams of the drug lincomycin is to be given for each kilogram of a person's weight the drug is be mixed with 250 cc o
krok68 [10]

Answer:

you need to convert pounds to kilograms. 196 pounds is 88.904 kilograms. The directions tell you that 20 milligrams of the drug is to be administered for each kilogram of a person's weight. Now you need to multiply 88.904 by 20. That should give you 1778.08 milligrams of lincomycin. You would then mix 250 cc's of saline solution to the 1778.08 milligrams of lincomycin; but I think its just asking you how much lincomycin to administer.

at what rate per minute should the 250 cc solution be adminstered

4 0
3 years ago
Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
3 years ago
30 treadmills to 36 elliptical machines the ratio in simplest form
Goshia [24]
30 treadmills : 36 ellipticals
this could be written in a few ways, but i am going to write it as a fraction. since treadmills come first, you put 30/36.

now that you have your fraction you have to find the GCF (greatest common factor) of the two numbers. the GCF is 6, so you have to divide 30 treadmills by 6, and 36 ellipticals by 6.
30/6=5
36/6=6

5/6 or 5:6 is the simplified ratio of treadmills to ellipticals



comment for any questions!!
4 0
3 years ago
Steven estimates how long his computer repairs will take. He discovers that ABC Tech and Tech Squad will charge the
katrin2010 [14]

You didn't include the costs of doing repairs at both computer repair firms. I fixed that for you.

ABC Tech ------- $20 service charge plus $15 per hour.

Tech squad ------- $30 service charge plus $10 per hour.

Answer:

Steven's estimate of the repair time is 2 hours.

Step-by-step explanation:

Now in this case, we were told that ABC Tech normally charges $20 service charge and $15 per hour of computer repair service. The second tech firm charges $30 service charge and $10 per hour for computer repair service. We are now simply required to find out or calculate the number of hours of computer repair service whereby the cost of doing repairs at both tech firms become equal.

Let us use "x" to represent that unknown number of hours. The equation needed to calculate this is:

20 + 15x = 30 + 10x

We then pair like terms

15x - 10x = 30 - 20

5x = 10

x = 10/5

x = 2

Therefore the number of hours of computer repair service whereby the cost of doing repairs at both tech firms become equal is 2 hours.

8 0
3 years ago
Which of the following points is a solution of the inequality y &lt; |x - 2|?
crimeas [40]

Answer:

(-2,0)

Step-by-step explanation:

y < |x - 2|

Substitute the points in and check

(-2,0)

0 < |-2 - 2|

0 < |-4|

0 < 4  True

(2,1)

1 < |2 - 2|

1 < |0|

1 < 0  False

(2,0)

0 < |2 - 2|

0 < |0|

0 < 0 False

3 0
3 years ago
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