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Georgia [21]
3 years ago
8

Can somebody help me with this one. It says use the vertical line test to determine which graph represents a function

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

Only option C shows a function

Step-by-step explanation:

The vertical line test is a visual way to determine if a curve is a graph of a function or not. A function can only have one output, y, for each unique input, x. This means that a vertical line made in the domain of the function can crosses the curve of the function only once. If it crosses the curve of the function more than once, then the curve is not a function.

In option A, a vertical line would cross two values, so it is not a function.

The curve of option B is a vertical line itself, so a vertical line would intersect an infinite amount of points; then it is not a function.

Option C is a function because a vertical line would only intersect the function's curve (which is a line) once.

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</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

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Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

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