Answer:
(a) Circle Q is 9.4 units to the center of circle P
(b) Circle Q has a smaller radius
Step-by-step explanation:
Given


Solving (a): The distance between both
The equation of a circle is:

Where


P and Q can be rewritten as:


So, for P:


For Q:


The distance between them is:

Where:
--- 
--- 
So:





Solving (b): The radius;
In (a), we have:
--- circle P
--- circle Q
By comparison

<em>Hence, circle Q has a smaller radius</em>
Answer:
$2,476.67
Step-by-step explanation:
Data provided in the question:
Annual insurance amount paid = $0.40 per $100 on his $455,000 home
Monthly mortgage payments = $2325.00
Now,
Annual insurance amount = [ $0.40 ÷ $100 ] × $455,000
= $1,820
Therefore,
Monthly insurance amount = [ Annual insurance amount ] ÷ 12
= $1,820 ÷ 12
= $151.67
Therefore,
His total monthly payment
= Monthly mortgage payments + Monthly insurance amount
= $2325.00 + $151.67
= $2,476.67
Answer:
40
Step-by-step explanation:
Answer:
171.65
Step-by-step explanation:
A=2AB+(a+b+c)h
AB=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c
2
Solving forA
A=ah+bh+ch+1
2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=5·10+5·10+5·10+1
2·﹣54+2·(5·5)2+2·(5·5)2﹣54+2·(5·5)2﹣54≈171.65064