From selling livestock and handicraft like pottery.
In metallic bonding (bonding between two metals), electrons are shared between the atoms in the substance.
We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
Answer:
0 587 mL
Explanation:
First we convert 180 grams of HCl into moles, using its molar mass:
- 180 g ÷ 36.46 g/mol = 4.94 mol HCl
Now we can <u>use the number of moles and the given concentration to calculate the required volume</u>, applying the <em>definition of molarity</em>:
- Molarity = moles / liters
- Liters = Moles / molarity
- 4.94 mol / 8.40 M = 0.588 L
Finally we <u>convert liters into milliliters</u>:
The closest answer is option C, 587 mL.
Answer:
The correct answer is C. The average score on the biology test was 78%. It only has a few words in it, but have very specific so we can imsgine it in our heads, it'll also be the best scientific investigation.
(Hope this helps) Sky