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Paha777 [63]
3 years ago
15

If .75 moles of ammonia is needed, how many grams of nitrogen will be consumed?

Chemistry
1 answer:
MrMuchimi3 years ago
5 0

We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.

The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.

Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-

N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)

According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, \frac{1 X 0.75}{2} moles = 0.375 moles of nitrogen is required.

Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.

Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.


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Answer:

IF the fruit juice contains a high level of vitamin C, THEN the preventative effectiveness against common cold increases.

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The hypothesis is a testable explanation of a scientific investigation. It aims at predicting the outcome of the experiment. One feature of the hypothesis is that it must be testable. The hypothesis is usually written in an "IF, THEN" format.

This question is regarding an experiment to test the amount of vitamin C in fruit juice. The vitamin C is thought to be an effective preventative against common cold. Hence, the hypothesis connects the effect on common cold (dependent variable) with the amount of vitamin C (independent variable). The hypothesis can be written as:

IF the fruit juice contains a high level of vitamin C, THEN the preventative effectiveness against common cold increases.

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Refer to the following balanced equation in which ammonia reacts with nitrogen monoxide to produce nitrogen and water.
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2.714 mole of helium has a mass of ______ grams.<br><br> (Enter just the number for this one.)
kifflom [539]

Hello!

To find the mass of helium, we need to multiply the total moles by the mass of helium. We are given 2.714 moles of helium, and the mass of helium is about 4.00 grams. Now, we multiply the two values together to get the grams.

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According to the number of significant figures, 2.714 moles of helium has a mass of 10.9 grams (exact value: 10.856 grams).

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An energy of 6.8 x 10^-19 J/atom is required to cause an aluminum atom on a metal surface to lose an electron.
Nana76 [90]

Wavelength of the light is 2.9 × 10⁻⁷ m.

<u>Explanation:</u>

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where E is the energy of the photon

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From the above equation, we can find the frequency by rearranging the equation as,

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ν × λ = c

It can be rearranged to get λ as,

λ = c / ν

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