If .75 moles of ammonia is needed, how many grams of nitrogen will be consumed?

Chemistry

1 answer:

MrMuchimi3 years ago

5 0

We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.

The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.

Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-

N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)

According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, $\frac{1 X 0.75}{2}$ moles = 0.375 moles of nitrogen is required.

Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.

Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.

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for the following reaction: 1 CuO + 1 H2 --> 1 Cu +1H2O, what is the quantity of moles of H2O when there are 240 grams of CuO

Ber [7]

Considering the reaction stoichiometry, the quantity of moles of H₂O produced is 3.02 moles.

The balanced reaction is:

CuO + H₂ → Cu + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CuO= 1 mole
H₂= 1 mole
Cu= 1 mole
H₂O= 1 mole

The molar mass of the compounds present in the reaction is:

CuO= 79.55 g/mole
H₂= 2 g/mole
Cu= 63.55 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:

CuO= 1 mole× 79.55 g/mole= 79.55 grams
H₂= 1 mole× 2 g/mole= 2 grams
Cu= 1 mole× 63.55 g/mole= 63.55 grams
H₂O: 1 mole× 18 g/mole= 18 grams

Then, it is possible to determine the moles of H₂O necessary by the following rule of three: If by reaction stoichiometry 79.55 grams of CuO produces 1 mole of H₂O, 240 grams of CuO produces how many moles of H₂O?

$molesofH_{2} O=\frac{240 grams of CuOx 1 mole ofH_{2} O }{79.55 grams of CuO}$