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BARSIC [14]
4 years ago
13

An investor bought 400 shares of stock, some at $7.00 per share and some at $1.00 per share. If the total cost was $1450.00, how

many shares of each stock did the investor buy?
Mathematics
1 answer:
Alja [10]4 years ago
4 0
57 at 7.oo dollars is 399 so he bought 1 more at 1 dollar
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The histogram shows the prices for six-packs of adult socks and six-packs of kid socks at a store. What is true about the variab
Agata [3.3K]

Answer:

a. There is more variability in the prices of kid socks because they have a greater range.

Step-by-step explanation:

A measure of variability is a summary statistic that represents the amount of dispersion in a dataset. Common examples are range, interquartile range (IQR), variance, and standard deviation.

From the histogram

Highest Number of Packs of Adult Socks = 7

Lowest Number of Packs of Adult Socks = 5

Range = 7 - 5 =2

Highest Number of Packs of Kid Socks = 7

Lowest Number of Packs of Kid Socks = 4

Range = 7-4 = 3

We conclude that there is more variability in the prices of kid socks because they have a greater range.

The correct option is A.

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3 years ago
Solve this inequality algebracially. |3-x|>10
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Answer:

x < -7 or x > 13

Step-by-step explanation:

3 - x < -10 or 3 - x > 10

-x < -13      or    -x > 7

x > 13         or    x < -7

Answer: x < -7 or x > 13

8 0
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Step-by-step explanation:

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Is 4y^2*3y^5=12y^10 true or false.
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A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
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