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BARSIC [14]
3 years ago
13

An investor bought 400 shares of stock, some at $7.00 per share and some at $1.00 per share. If the total cost was $1450.00, how

many shares of each stock did the investor buy?
Mathematics
1 answer:
Alja [10]3 years ago
4 0
57 at 7.oo dollars is 399 so he bought 1 more at 1 dollar
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8/11

Step-by-step explanation:

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Subtract L from both sides. 
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<span>S−L=−rL</span>
2)Divide by L on both sides.
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find the greatest number that exactly divide 16 and 24. ind the ornatost number that diido 20 and 20 min​
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Step-by-step explanation:

The greatest common factor (GCF) is the largest common factor that the numbers share. Here, 8 is the largest common factor of 16 and 24. So the GCF of 16 and 24 is 8.

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1. Solve the given quadratic equations by extracting square roots. Provide an extra sheet for your solutions.​
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SOMEONE PLZ HELP ME!!!! I WILL GIVE BRAINLIEST!!!
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Answer:

Step-by-step explanation:

Let the quadratic equation of the function by the points in the given equation is,

f(x) = ax² + bx + c

If the points lying on the graph are (-3, -10), (-4, -8) and (0, 8),

For (0, 8),

f(0) = a(0)² + b(0) + c

8 = c

For a point (-3, -10),

f(-3) = a(-3)² + b(-3) + 8

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For (-4, -8),

f(-4) = a(-4)² + b(-4) + 8

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-16 = 16a - 4b

4a - b = -4 ------(2)

Subtract equation (1) from equation (2)

(4a - b) - (3a - b) = -4 + 6

a = 2

From equation (1),

6 - b = -6

b = 12

Function will be,

f(x) = 2x² + 12x + 8

     = 2(x² + 6x) + 8

     = 2(x² + 6x + 9 - 9) + 8

     = 2(x² + 6x + 9) - 18 + 8

     = 2(x + 3)² - 10

By comparing this function with the vertex form of the function,

y = a(x - h)² + k

where (h, k) is the vertex.

Vertex of the function 'f' will be (-3, -10)

And axis of symmetry will be,

x = -3

From the given graph, axis of the symmetry of the function 'g' is; x = -3

Therefore, both the functions will have the same axis of symmetry.

y-intercept of the function 'f' → y = 8 Or (0, 8)

y-intercept of the function 'g' → y = -2 Or (0, -2)

Therefore, y-intercept of 'f' is greater than 'g'

Average rate of change of function 'f' = \frac{f(b)-f(a)}{b-a} in the interval [a, b]

                                                               = \frac{f(-3)-f(-6)}{-3+6}

                                                               = \frac{-10-8}{3}

                                                               = -6

Average rate of change of function 'g' = \frac{g(b)-g(a)}{b-a}

                                                                = \frac{g(-3)-g(-6)}{-3+6}

                                                                = \frac{7+2}{-3+6}

                                                                = 3

Therefore, Average rate of change of function 'f' is less than 'g'.

6 0
3 years ago
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