Teps to go<br> h(x) = x2 + 5x + 6<br> write in factored form

2 quarts = how many gallons

evablogger [386]

Answer:

0.5 Gallons

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A number, X, rounded to 1 decimal place is 3,7<br> Write down the error interval for x,

sp2606 [1]

Answer:

The error interval for x is:

[3.65,3.74]

Step-by-step explanation:

The number after rounding off is obtained as:

3.7

We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

3.65 3.66 3.67 3.68 3.69 3.70 3.71 3.72 3.73 3.74

( Because if we have to round off a number present in decimals to n place then if there is a number greater than or equal to 5 at n+1 place then it will result to the one higher digit at nth place on rounding off and won't change the digit if it less than 5 )

Hence, the error interval is:

[3.65,3.74]

6 0

3 years ago

What is 245 divided by 15

liraira [26]

16.33333 (just put a line over the 3 because it just keeps on going and thats what the line shows)

4 0

3 years ago

Read 2 more answers

Can you explain how you got the answer?

Paladinen [302]

Answer:

Find the stated lengths and values of rectangle M 26 N

LMNO. Round to the nearest tenth. P 5a - 7 2a + 8 240 9. MO

10. LP O 11. LM 12. ZNMO Find the missing leng..

4 0

2 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

Teps to go h(x) = x2 + 5x + 6 write in factored form