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3 years ago

Solve this Proportion. Will give BRAINLIST!!

Mathematics

1 answer:

Korolek [52]3 years ago

7 0

Answer:

x=19.3333

Step-by-step explanation:

Cross multiply

6(x-3)=14*7

6x-18=98

6x=98+18

6x=116

x=19.3333

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Mr. Harnish purchased a Landau Atlantis ski boat for $63,865. He got a 7 year compound interest loan with an interest rate of 2.

Dahasolnce [82]

Answer:

$713218.64

Step-by-step explanation:

7 0

3 years ago

Write a quadratic function whose zeros are -12 and -2.

AnnZ [28]

Answer:

(x+12) (x+2)

x(x+12)+2(x+12)

x^2+12x+2x+24

x^2+14x+24

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Angle α lies in quadrant II , and tanα=−125 . Angle β lies in quadrant IV , and cosβ=35 .

Artist 52 [7]

Answer:

$cos(\alpha+\beta)=\frac{33}{65}$

Step-by-step explanation:

step 1

Find cos α

we know that

$tan^2(\alpha)+1=sec^2(\alpha)$

we have

$tan(\alpha)=-\frac{12}{5}$

substitute

$(-\frac{12}{5})^2+1=sec^2(\alpha)$

$sec^2(\alpha)=\frac{144}{25}+1$

$sec^2(\alpha)=\frac{169}{25}$

$sec(\alpha)=\pm\frac{13}{5}$

Remember that Angle α lies in quadrant II

sec α is negative

$sec(\alpha)=-\frac{13}{5}$

Find the value of cos α

$cos)\alpha)=\frac{1}{sec(\alpha)}$

$cos(\alpha)=-\frac{5}{13}$

step 2

Find sin α

we know that

$tan(\alpha)=\frac{sin(\alpha)}{cos(\alpha)}$

$sin(\alpha)=tan(\alpha)cos(\alpha)$

we have

$tan(\alpha)=-\frac{12}{5}$

$cos(\alpha)=-\frac{5}{13}$

substitute

$sin(\alpha)=(-\frac{12}{5})(-\frac{5}{13})$

$sin(\alpha)=\frac{12}{13}$

step 3

Find sin β

we know that

$sin^2(\beta)+cos^2(\beta)=1$

we have

$cos(\beta)=\frac{3}{5}$

substitute

$sin^2(\beta)+(\frac{3}{5})^2=1$

$sin^2(\beta)=1-(\frac{3}{5})^2$

$sin^2(\beta)=1-\frac{9}{25}$

$sin^2(\beta)=\frac{16}{25}$

$sin(\beta)=\pm\frac{4}{5}$

Remember that

Angle β lies in quadrant IV

sin β is negative

$sin(\beta)=-\frac{4}{5}$

step 4

Find cos(α−β)

we know that

$cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)$

we have

$cos(\alpha)=-\frac{5}{13}$

$cos(\beta)=\frac{3}{5}$

$sin(\alpha)=\frac{12}{13}$

$sin(\beta)=-\frac{4}{5}$

substitute the given values

$cos(\alpha+\beta)=(-\frac{5}{13})(\frac{3}{5})-(\frac{12}{13})(-\frac{4}{5})$

$cos(\alpha+\beta)=(-\frac{15}{65})+(\frac{48}{65})$

$cos(\alpha+\beta)=\frac{33}{65}$

7 0

4 years ago

Find the first five terms of the sequence.

blagie [28]

Hello :

the sequence.
a(1) =2, a(n+1) =a(n) + 3 is arithmetique (common ratio : 3)
 the first five terms are : 2,5,8,11,14

6 0

4 years ago

Please HELPPPPP!!! I DONT KNOW WHY IM GETTING THEM WRONG

Nady [450]

Answer:

n = -33

Step-by-step explanation:

Let n = number

Sum of a number and 9

(n+9)

is tripled

3(n+9)

the result is six less then twice the number

2n-6

3(n+9) = 2n-6

Distribute

3n+27 = 2n-6

Subtract 2n from each side

3n-2n +27 = -6

n +27 = -6

Subtract 27 from each side

n+27-27 = -6-27

n =-33

3 0

3 years ago