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zubka84 [21]
3 years ago
7

The graph below displays the wrist circumferences and heights of six students in Alyssa’s classroom.

Mathematics
2 answers:
Nikolay [14]3 years ago
6 0

Answer: The answer would be D: No because the wrist circumference of 16 cm is paired with two heights.

Step-by-step explanation: I just took the quiz on Edge, I hope this helps!

coldgirl [10]3 years ago
5 0

Answer:

Option D(No because the wrist circumference of 16 cm is paired with two heights.


Step-by-step explanation:

In the given graph we have  set of points representing the wrist circumferences and heights of six students in Alyssa’s classroom.

x axis  represents the wrist circumference while  y axis represent the height.

Any relation is called a function if for one value of x we have only one value of y. If the graph passes the vertical line test that is if a vertical line drawn touches the graph at only one point then the graph is called a function.In the given graph for x value x=16 there are two y values 162 and 165.So the graph is not a function.

Among all the options Option D(No because the wrist circumference of 16 cm is paired with two heights.) is the right answer.

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Phantasy [73]

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28.5 cm²

Step-by-step explanation:

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6 0
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ehidna [41]
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8 0
3 years ago
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ehidna [41]

Answer:

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6 0
3 years ago
You have to find the domain and range
Dahasolnce [82]

Answer:

First off, we look for which circles are open or closed.

We start with an open interval since the circle on the left is open and end with a closed interval since the circle on the right is closed.

Domain is all x values, Range is all y values

The graph shows the continous function going from -3 to 1 on the x axis.

According to the circles, this means our domain will be (-3,1].

Now, the range doesn't care about if its closed or not. So we can say the graph is on the y axis from -4 and 0. This means the range is -4<y<0

I used different notations for both just incase you need to represent your answer differently :)

-3<x<1 & (-3,1] . Range is [-4,0]. 0>y>-4 looks correct as-well.

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