8x^2 -3 = 2
add 3 to each side
8x^2 = 5
divide by 8
x^2 =5/8
take the square root of each side
x = +- sqrt (5/8)
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
Answer:
a
Step-by-step explanation:
2 angles. 1 sude
Answer:
The equation is given by:

Step-by-step explanation:
Sine function:
Has the following format:

In which A is the amplitude and
is the period.
Suppose you know the temperature is 80 degrees at midnight and the high and low temperature during the day are 89 and 71 degrees
This means that the amplitude of the sinusoidal variation function is 89 - 80 = 80 - 71 = 9. This means that 
During a 24-hour day, which means that the period is 24. So




So the variation is:

Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.
Initial temperature of 80, so:
