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Zolol [24]
3 years ago
14

What is the area of the regular hexagon ABCEF? Explain your reasoning.

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

1350\sqrt{3} units²

Step-by-step explanation:

The regular hexagon consists of 6 equiangular triangles

The area (A) of a equilateral triangle is calculated as

A = \frac{s^2\sqrt{3} }{4} ( s is the side length )

Here s = 30 , then

A = \frac{30^2\sqrt{3} }{4} = \frac{900\sqrt{3} }{4} = 225\sqrt{3} units²

Thus the area of the regular hexagon is

area = 6 × 225\sqrt{3}

        = 1350\sqrt{3} units² ← exact value

         ≈ 2338.3 units² ( to 1 dec. place )

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Step-by-step explanation:

Descarte's rule of signs gives bounds on the number of positive and negative real roots. The numbers it gives may be reduced by multiples of 2, as complex roots will come in conjugate pairs. The total number of roots of all kinds will match the degree of the polynomial.

Synthetic division is essentially polynomial long division with some modifications:

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<h3>a) </h3>

The signs of the terms of the given polynomial are + - - - +. There are two sign changes, so 2 possible positive real roots.

When the signs of the odd-degree terms are changed, the signs become + + - + +. There are still two sign changes, so 2 possible negative real roots.

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<h3>b)</h3>

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<h3>c)</h3>

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<h3>d)</h3>

The second attachment shows synthetic division by the factor (x+4).

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