All categories

2 years ago

Solve for x. 8x2−3=2

Mathematics

1 answer:

gavmur [86]2 years ago

7 0

8x^2 -3 = 2

add 3 to each side

8x^2 = 5

divide by 8

x^2 =5/8

take the square root of each side

x = +- sqrt (5/8)

You might be interested in

Find the value of x and y

jonny [76]

The answer is C. The easiest way to find this is by setting the top two angles added together to 180 because they divide a straight line. The just plug the numbers in and you get C

3 0

2 years ago

Read 2 more answers

LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the

Semmy [17]

Answer:

The wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ East of North with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector $\overrightarrow{DD'}$ is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

$|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)$

and the direction is $\alpha$ east of north as shown in the figure,

$\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)$

From the figure,

$|AB|=|OA-OB|$

$\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|$

$\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|$

$\Rightarrow |AB|=45.52$ miles

Again, $|PQ|=|OP-OQ|$

$\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=46.42$ miles

Now, from equations (i) and (ii), we have

$|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01$ miles, and

$\tan \alpha=\frac{|46.42|}{|45.52|}$

$\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}$

Hence, the wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ E astof North with respect to the destination point.

5 0

2 years ago

Describe how to transform (^6 sqrt x^5)^7 into an expression with a rational exponent.

solniwko [45]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\left(\sqrt[6]{x^5}\right)^7\implies \left( x^{\frac{5}{6}} \right)^7\implies x^{\frac{5}{6}\cdot 7} \implies x^{\frac{5\cdot 7}{6}}\implies x^{\frac{35}{6}}$

5 0

3 years ago

The vectors x and y are unit vectors that make and angle of 30 degrees with each other. Calculate the value of | 2x + y | and th

ICE Princess25 [194]

Answer: the value of | 2x + y | = 1.39

the direction of 2x + y = 21°

Step-by-step explanation:

Given that the vectors x and y are unit vectors that make and angle of 30 degrees with each other.

Let assume that unit vector x is along the positive x-axis, and unit vector y is at +30°.

Therefore

2x-y=

2< 1,0 > - < cos(30),sin(30) >

=<2-(√2)/2, 0-1/2>

and

|2x-y|=√((2-(√2)/2)² + (-1/2)^2)

=1.3862

Therefore the value of | 2x + y | = 1.39

=atan((-1/2)÷(2-(√2)/2))

=atan(1.29289/-0.5)

=-0.369 radians

= -21.143°

Therefore the direction of 2x + y is

21°

5 0

2 years ago

An arc on a circle measures 250 degrees. Within range which range is the radian measure of the central angle?

blondinia [14]

If the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.

Given that the arc of a circle measures 250 degrees.

We are required to find the range of the central angle.

Range of a variable exhibits the lower value and highest value in which the value of particular variable exists. It can be find of a function.

We have 250 degrees which belongs to the third quadrant.

If 2π=360

x=250

x=250*2π/360

=1.39 π radians

Then the radian measure of the central angle is 1.39π radians.

Hence if the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.

Learn more about range at brainly.com/question/26098895

#SPJ1

8 0

11 months ago