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andrew11 [14]
3 years ago
14

What is the quotient of StartFraction negative 8 x Superscript 6 Baseline Over 4 x Superscript negative 3 Baseline EndFraction?

StartFraction x Superscript 9 Baseline Over 32 EndFraction 4x9 Negative StartFraction 12 Over x squared EndFraction –2x9
Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

Option D.

Step-by-step explanation:

We need to find the quotient of  

\dfrac{-8x^6}{4x^{-3}}

It can rewritten as

\dfrac{-8}{4}\times \dfrac{x^6}{x^{-3}}

-2\times x^{6-(-3)}      [\because \dfrac{a^m}{a^n}=a^{m-n}]

-2x^{6+3}  

-2x^{9}  

The required expression is -2x^{9} .

Therefore, the correct option is D.

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Please its past due, will give brainlist, there is a pt. 2
Yanka [14]

Answer:

First we add 7 on both sides

-7x+3y= -6.3

+7. +7

___________

then we simply

-7x + 7x= -1

bring down the 3y

-6.3+ 7x = 0.23

So, -1x+3y=0.7

2y = 0.7

___ __

2. 2

y = 0.35 or 35!!

Step-by-step explanation:

Hope this helps

5 0
2 years ago
Read 2 more answers
5(10k+1)+2(2+8k) simplify
iVinArrow [24]
Firstly expand it: 50k + 5 + 4 + 16k
Collect like terms: (50k + 16K) + (5 + 4)
Simplify: 66k + 9.
4 0
3 years ago
HELP PLS Describe two real-life situations that could be represented by the graph below
aev [14]

the amount you walk by the hour?

x axis- distance

y axis- hours

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4 0
2 years ago
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Ayush and sumit take two different routes to school. Ayush's route is 1km 2hm long while sumit route is 2hm 30dam long while rou
emmasim [6.3K]

Answer:

Ayush's route is 0.7 km or 700m longer than Sumit route.

Step-by-step explanation:

Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.

We know that,

1 km = 10 hm

1 dam = 0.1 hm

Using these conversions we get

Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm

Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm

Ayush's route is longer.

Difference = 12 hm - 5 hm = 7 hm = 0.7 km            [1 km = 10 hm]

Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.

4 0
3 years ago
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Determine the inverse of the function. (show work please)
uysha [10]

Answer:

This is easy -- it's just a list of steps.  At this level, the problems are pretty simple.

Let's just do one, then I'll write out the list of steps for you.

Find the inverse of f( x ) = -( 1 / 3 )x + 1

STEP 1:  Stick a "y" in for the "f(x)" guy:

y = -( 1 / 3 )x + 1

STEP 2:  Switch the x and y

                   ( because every (x, y) has a (y, x) partner! ):

x = -( 1 / 3 )y + 1

STEP 3:  Solve for y:

x = -( 1 / 3 )y + 1 ... multiply by 3 to ditch the fraction ... 3x = -y + 3 ... ditch the +3 ... subtract 3 from both sides ... 3x - 3 = -y ... multiply by -1 ... -3x + 3 = y ... y = -3x + 3

STEP 4:  Stick in the inverse notation, f^( -1 )( x )

f^( -1 )( x ) = -3x + 3

Step-by-step explanation:

5 0
3 years ago
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